LeetCode Spiral Matrix II

class Solution {
    public:
            vector<vector<int> > generateMatrix(int n) {
                vector<vector<int> > matrix;
                if (n < 1) return matrix;

                for (int i=0; i<n; i++) {
                    matrix.push_back(vector<int>(n, 0));
                }
                int left = 0, top = 0, right = n - 1, bottom = n - 1;
                int last = 1;
                while (left <= right && top <= bottom) {
                    last = circle_walk(last, left, top, right, bottom, matrix);
                    left++, top++, bottom--, right--;
                }
                return matrix;
            }

            int circle_walk(int start, int left, int top, int right, int bottom, vector<vector<int> >& map) {
                    int rows = 0;
                    if (map.size() < 1 || map[0].size() < 1) return start;
                            
                    // top row
                    for (int i=left; i<=right; i++) {
                        map[top][i] = start++;
                    }

                    // right col
                    for (int i=top+1; i<=bottom; i++) {
                       map[i][right] = start++;
                    }
                    
                    // bottom row
                    for (int i=right-1; bottom != top && i>=left; i--) {
                        map[bottom][i] = start++;
                    }

                    // left col
                    for (int i=bottom-1; left != right && i>top; i--) {
                        map[i][left] = start++;
                    }
                    return start;
            }
};

再水一发

第二轮:

Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order.

For example,
Given n = 3,

You should return the following matrix:

[
 [ 1, 2, 3 ],
 [ 8, 9, 4 ],
 [ 7, 6, 5 ]
]
 1 class Solution {
 2 public:
 3     vector<vector<int> > generateMatrix(int n) {
 4         vector<vector<int> > matrix(n, vector<int>(n, 0));
 5         
 6         if (n < 1) {
 7             return matrix;
 8         }
 9         
10         int xn = n;
11         int yn = n;
12         
13         int col = -1;
14         int row = 0;
15         
16         int seq = 1;
17         
18         while (true) {
19             for (int i=0; i<xn; i++) matrix[row][++col] = seq++;        
20             if (--yn == 0) break;
21             
22             for (int i=0; i<yn; i++) matrix[++row][col] = seq++;
23             if (--xn == 0) break;
24             
25             for (int i=0; i<xn; i++) matrix[row][--col] = seq++;
26             if (--yn == 0) break;
27             
28             for (int i=0; i<yn; i++) matrix[--row][col] = seq++;
29             if (--xn == 0) break;
30         }
31         
32         return matrix;
33     }
34 };

 

posted @ 2014-05-27 15:47  卖程序的小歪  阅读(168)  评论(0编辑  收藏  举报