RCC 2014 Warmup (Div. 2)

A.

读题读了好久。。。

 1 #include <stdio.h>
 2 #include <string.h>
 3 #include <iostream>
 4 const int INF=1<<28;
 5 using namespace std;
 6 int main()
 7 {
 8     int c,d;
 9     int n,m,k;
10     while(cin>>c>>d)
11     {
12         cin>>n>>m>>k;
13         if (n*m <= k)
14         {
15             puts("0");
16             continue;
17         }
18         int ex = (n*m-k)/n;
19         if ((n*m-k)%n!=0)
20         ex += 1;
21         int ey = n*m-k;
22         int ans = INF;
23         for (int i = 0;i <= ex; i++)
24         for (int j = 0;j <= ey; j++)
25         {
26             if (n*i+j >= n*m-k)
27             {
28                 ans = min(ans,c*i+d*j);
29             }
30         }
31         cout<<ans<<endl;
32     }
33     return 0;
34 }
View Code

B.

开始排序+暴力。。写的好麻烦。。关键是题意不好弄懂。。理解了就好写了。。

 1 #include <stdio.h>
 2 #include <string.h>
 3 const int N=100005;
 4 int c[N];
 5 int main()
 6 {
 7     int n;
 8     scanf("%d",&n);
 9     int x,y,flag = 0;
10     memset(c,0,sizeof(c));
11     for (int i = 0; i < n; i++)
12     {
13         scanf("%d%d",&x,&y);
14         if (c[y] < x)
15         {
16             flag = 1;
17             break;
18         }
19         else if (c[y]==x)
20             c[y]++;
21     }
22     if (!flag)
23         puts("YES");
24     else
25         puts("NO");
26 }
View Code


C.

直接暴力。。

 1 #include <stdio.h>
 2 #include <string.h>
 3 const int N=1002;
 4 int vis[N][N];
 5 int main()
 6 {
 7     int n,k;
 8     while(~scanf("%d%d",&n,&k))
 9     {
10         int flag = 0;
11         int ans = 0;
12         memset(vis,0,sizeof(vis));
13         for (int i = 1; i <= n; i++)
14         {
15             int cnt = 0;
16             for (int j = 1; j <= n; j++)
17             {
18                 if (i==j||vis[i][j])
19                     continue;
20                 if (cnt==k)
21                     break;
22                 vis[i][j] = 1;
23                 vis[j][i] = 2;
24                 cnt++,ans++;
25             }
26             if (cnt!=k)
27             {
28                 flag = 1;
29                 break;
30             }
31         }
32         if (flag)
33         {
34             puts("-1");
35             continue;
36         }
37         printf("%d\n",ans);
38         for (int i = 1; i <= n; i++)
39         {
40             for (int j = 1; j <= n; j++)
41                 if (vis[i][j]==1)
42                 {
43                     printf("%d %d\n",i,j);
44                 }
45         }
46     }
47     return 0;
48 }
View Code

 

 

posted @ 2014-04-18 09:37  N_ll  阅读(197)  评论(0)  编辑  收藏  举报