mysql根据传递的参数判断是否对语句进行UNION ALL

没有办法在语句中直接使用if条件(存储过程可以),所以可以利用下面方法实现

方法1:

SELECT *
FROM (
SELECT *, 1 as source_table
FROM hljtxeip_workday_holiday
WHERE
`year` = YEAR (
NOW())
AND `month` = MONTH (
NOW())
AND `type` = '工作日'

UNION ALL

SELECT *, 2 as source_table
FROM hljtxeip_workday_holiday
WHERE
`year` = YEAR (
NOW())
AND `month` = MONTH(DATE_SUB(NOW(), INTERVAL 1 MONTH))
AND `type` = '工作日' and 1 = 1
) AS combined_tables;

 

方法2:

SELECT *
FROM (
SELECT *, 1 as source_table
FROM hljtxeip_workday_holiday
WHERE
`year` = YEAR (
NOW())
AND `month` = MONTH (
NOW())
AND `type` = '工作日'

UNION ALL

SELECT *, 2 as source_table
FROM hljtxeip_workday_holiday
WHERE
`year` = YEAR (
NOW())
AND `month` = MONTH(DATE_SUB(NOW(), INTERVAL 1 MONTH))
AND `type` = '工作日'
) as combined_tables
WHERE (CASE WHEN 1 = 2 THEN (source_table = 1) ELSE (1 = 1) END)

posted @   20211103  阅读(4)  评论(0编辑  收藏  举报
相关博文:
阅读排行:
· TypeScript + Deepseek 打造卜卦网站:技术与玄学的结合
· 阿里巴巴 QwQ-32B真的超越了 DeepSeek R-1吗?
· 【译】Visual Studio 中新的强大生产力特性
· 【设计模式】告别冗长if-else语句:使用策略模式优化代码结构
· AI与.NET技术实操系列(六):基于图像分类模型对图像进行分类
点击右上角即可分享
微信分享提示