Golang--函数签名相同
Golang--函数签名相同
条件
必须函数的函数名，参数和返回值(类型，个数，顺序)都相同。
验证
例子：
定义函数类型，让相同签名的函数自动实现某个接口。
Negtive:
package interfaceTest
import (
"fmt"
"testing"
)
type IntString interface {
test(a int ,s string) (int ,string)
}
type likeIntString func(s string ,i int) (int ,string)
func (i likeIntString) testaaa(ii int, s string) (int, string) {
return i(s, ii)
}
func TestInterface(t *testing.T){
var tt IntString = likeIntString(func(s string, i int) (int, string) {
return i,s
})
i, s := tt.testaaa(7, "dfdf")
fmt.Println(i,s)
}
# Go_test/src/interface/interfaceTest [Go_test/src/interface/interfaceTest.test]
.\interface_test.go:21:6: cannot use likeIntString(func literal) (type likeIntString) as type IntString in assignment:
likeIntString does not implement IntString (missing test method)
.\interface_test.go:25:12: tt.testaaa undefined (type IntString has no field or method testaaa)
Postive
package interfaceTest
import (
"fmt"
"testing"
)
type IntString interface {
test(a int ,s string) (int ,string)
}
type likeIntString func(s string ,i int) (int ,string)
func (i likeIntString) test(ii int, s string) (int, string) {
return i(s, ii)
}
func TestInterface(t *testing.T){
var tt IntString = likeIntString(func(s string, i int) (int, string) {
return i,s
})
i, s := tt.test(7, "dfdf")
fmt.Println(i,s)
}
