一、JUnit4 jar包下载
链接:https://pan.baidu.com/s/1AdeVGGikcY5dfL151ZnWHA
提取码:h1am
下载完成后,解压一下即可。
二、导入JUnit4 jar包
1.打开eclipse,右击你要进行单元测试的类所在的java项目,选择“Properties”选项
2.在弹出的对话框中选择“Java Build Path”----->"Add Library" 选项,进行构建JUnit4路径
3.在弹出的“Add Library”对话框中选择“JUnit”选项,单击“Next”按钮,在下拉列表中选择“JUnit4”,点击“Finish”,完成添加
4.添加完成后,单击“Apply”,应用变更,单击“OK”按钮,JUnit4构建成功,即可以使用JUnit4框架进行单元测试。
三、用JUnit4对一个算法题编写测试用例,进行测试。
1.首先来看这个算法题:
这个算法题有几个条件:
(1)要从起始点走到终点结束
(2)这个线段上的所有的点都要走一遍,但是每个点只能经过一次,
(3)在任何位置都可以用0次或多次技能跳到第一个点和第N个点(最后一个点)以达到以上两个条件
(4)三个值的范围是[1,10000] 且1<=S,T<=N
(5)用任何走法都不能达到目的则输出-1
(6)输入的参数是0或负数的时候,输出-1
(7)输入的终点T大于总点数S的时候,输出-1
(8)当N=S=T>1的时候,想要到达终点,终点所在的这个点始终要经过两遍,所以永远无法满足条件,则输出-1
(9)当N=S=T=1的时候,不用走,直接到终点,需要发动0次技能
(10)当S=1,T=N的时候,从第一个点走到最后一个点即可,也不用发动技能,所以是0次
(11)当S=1,T<N的时候,需要发动一次一次技能
(12)当终点在起始点的右侧相邻点(即T-S=1)的时候,需要发动一次技能
(13)当起始点大于1(S>1),终点小于N(T<N)的时候,也是只需发动一次技能
图同上,但两个判定条件不一样,一个是起始点和终点相邻,一个是起始点和终点在第一个点和最后一个点中间
(14)当起始点大于1(S>1),终点为N(T=N)的时候,需要发动两次技能才能到达终点
根据以上分析,编写Java代码如下:
import java.util.Scanner;
public class Main66 {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String nn = sc.next();
String ss = sc.next();
String tt = sc.next();
new Main66().count(nn,ss,tt);
}
private static int count = -1;
public int count(String nn,String ss,String tt){
//判断输入的是否是非数字
boolean nIsNum = nn.matches("^(\\d{1,4}|10000)$");
boolean sIsNum = ss.matches("^(\\d{1,4}|10000)$");
boolean tIsNum = tt.matches("^(\\d{1,4}|10000)$");
if(nIsNum && sIsNum && tIsNum){
int n = Integer.parseInt(nn);
int s = Integer.parseInt(ss);
int t = Integer.parseInt(tt);
/*
*
* n<1 || s<1 || t<1 :判断负值和0值
* s==t && n!=s: 判断起始点和终点重合,并且总点数N>1(即永远无法到达终点)
* s>n || t>n: 判断起始点和终点对总点数n的越界
* s>t: 起始点是否大于终点
* */
if(n<1 || s<1 || t<1 || (s==t && n!=1) || s>n || t>n || s>t){
count = -1;
}else{
if(s==t && n==s && n==1){
count = 0;
}else if(s==1 && t==n){
count = 0;
}else if(s==1 && t<n){
count = 1;
}else if(t-n==1){
count = 1;
}else if(s>1 && t<n ){
count = 1;
}else if(s>1 && t==n){
count = 2;
}
}
}
System.out.println(count);
return count;
}
}
2.创建测试类,编写测试用例并执行
(1)右击“Main66”这个类,选择“New”---->"JUnit Text Case"
(2)在打开的“New JUnit Test Case”对话框中,项目路径,包名,要测试的类都是默认填好且正确的,检查无误,测试类的类名可以按照默认的“Main66Test”,也可以自己进行设置,
设置完成后,单击“Finish”按钮
(3)"Main66"的测试类就创建成功了
(4)根据上述编写算法题时列出的条件,一次性进行多组数据,每组数据多个参数的测试,以下是我写的对于这个算法题的测试用例
import static org.junit.Assert.*;
import java.util.Arrays;
import java.util.Collection;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.junit.runners.Parameterized;
import org.junit.runners.Parameterized.Parameters;
//1、更改默认的测试运行器为@RunWith(Parameterized.class)
@RunWith(Parameterized.class)
public class Main66Test {
//2、声明变量定义预期值和初始值
int expected = 0;//预期值
String input1 = "";//输入值1
String input2 = "";//输入值2
String input3 = "";//输入值3
//3、声明一个返回值为Collection的公共静态方法,并使用@Parameters进行修改
@Parameters
public static Collection<Object[]> t(){
return Arrays.asList(new Object[][]{
//汉字测试
{-1,"输入","2","2"},
{-1,"2","阿尔戈","2"},
{-1,"2","2","热"},
//字母测试
{-1,"a","2","2"},
{-1,"2","a","2"},
{-1,"2","2","w"},
//字符测试
{-1,"@","2","2"},
{-1,"2",".","2"},
{-1,"2","2","'"},
//边界值测试
{-1,"10001","2","2"},
{-1,"2","10001","2"},
{-1,"2","2","10001"},
{-1,"10000","2","2"},
{-1,"2","10000","2"},
{-1,"2","2","10000"},
{-1,"9999","2","2"},
{-1,"2","9999","2"},
{-1,"2","2","9999"},
//大数测试
{-1,"2222222222222222222222","2","2"},
{-1,"2","22222222222222222222222222","2"},
{-1,"2","2","222222222222222222222222222222222"},
//空格测试
{-1," ","2","2"},
{-1,"2"," ","2"},
{-1,"2","2"," "},
//tab测试
{-1," ","2","2"},
{-1,"2"," ","2"},
{-1,"2","2"," "},
//负值测试
{-1,"-1","2","2"},
{-1,"2","-1","2"},
{-1,"2","2","-1"},
//0值测试
{-1,"0","2","2"},
{-1,"2","0","2"},
{-1,"2","2","0"},
//起点和终点重合,但总点数不为1
{-1,"6","6","6"},
{-1,"6","1","1"},
//越界测试
{-1,"1","2","1"},
{-1,"1","1","2"},
{-1,"1","2","2"},
{-1,"6","6","2"},
{-1,"6","3","2"},
//判定覆盖和条件覆盖
{2,"6","2","6"},
{0,"6","1","6"},
{1,"6","1","5"},
{0,"1","1","1"},
{1,"6","2","3"},
{1,"6","2","4"},
{1,"6","1","2"},
});
}
//4、为测试类声明一个带有参数的公共构造方法,并在其中为变量赋值
public Main66Test(int expected,String input1,String input2,String input3){
this.expected = expected;
this.input1 = input1;
this.input2 = input2;
this.input3 = input3;
}
//5.执行测试方法
@Test
public void testCount() {
assertEquals(expected,new Main66().count(input1,input2,input3));
}
}
(5)右键单击“Main66Test”,执行测试用例
(6)结果及主要参数的含义如下
测试完成。
ps:一个初学者的总结和分享,如果有描述不当的地方,还请各位大佬指正,感谢。
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