cKK

摘要： Implement pow(x, n). double sum = 1; if (n > 0) { while ((n--) > 0) sum *= x; return sum; } else if (n < 0) { while ((n++) < 0) sum /= x; } return sum 阅读全文

摘要： Given a string containing just the characters'(',')','{','}','['and']', determine if the input string is valid.The brackets must close in the correct ... 阅读全文