// 题目:求n的阶乘和,即1!+2!+...+n! // 解法:在一个循环内部,用i从1到n进行遍历: // 1、先求出当前i的阶乘的值,再将当前从1到i的阶乘累加 // 2、求i的阶乘:(i-1)!*i long xxx_jieChen(int N) { int sum = 0; int curN = 1; for (int i = 1; i <= N; ++i) { curN *= i; sum += curN; } return sum; }
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