Rabin-Karp 字符串匹配算法

 

 

 

 

 1 public class Main  
 2 { 
 3     // d is the number of characters in the input alphabet 
 4     public final static int d = 256; 
 5       
 6     /* pat -> pattern 
 7         txt -> text 
 8         q -> A prime number 
 9     */
10     static void search(String pat, String txt, int q) 
11     { 
12         int M = pat.length(); 
13         int N = txt.length(); 
14         int i, j; 
15         int p = 0; // hash value for pattern 
16         int t = 0; // hash value for txt 
17         int h = 1; 
18       
19         //  pow(d, M-1)%q 
20         for (i = 0; i < M-1; i++) 
21             h = (h*d)%q; 
22       
23         // Calculate the hash value of pattern and first 
24         // window of text 
25         for (i = 0; i < M; i++) 
26         { 
27             p = (d*p + pat.charAt(i))%q; 
28             t = (d*t + txt.charAt(i))%q; 
29         } 
30       
31         // Slide the pattern over text one by one 
32         for (i = 0; i <= N - M; i++) 
33         { 
34       
35             // Check the hash values of current window of text 
36             // and pattern. If the hash values match then only 
37             // check for characters on by one 
38             if ( p == t ) 
39             { 
40                 /* Check for characters one by one */
41                 for (j = 0; j < M; j++) 
42                 { 
43                     if (txt.charAt(i+j) != pat.charAt(j)) 
44                         break; 
45                 } 
46       
47                 // if p == t and pat[0...M-1] = txt[i, i+1, ...i+M-1] 
48                 if (j == M) 
49                     System.out.println("Pattern found at index " + i); 
50             } 
51       
52             // Calculate hash value for next window of text: Remove 
53             // leading digit, add trailing digit 
54             if ( i < N-M ) 
55             { 
56                 t = (d*(t - txt.charAt(i)*h) + txt.charAt(i+M))%q; 
57       
58                 // We might get negative value of t, converting it 
59                 // to positive 
60                 if (t < 0) 
61                 t = (t + q); 
62             } 
63         } 
64     } 
65       
66     /* Driver program to test above function */
67     public static void main(String[] args) 
68     { 
69         String txt = "GEEKS FOR GEEKS"; 
70         String pat = "GEEK"; 
71         int q = 101; // A prime number 
72         search(pat, txt, q); 
73     } 
74 }

 

posted on 2019-03-08 14:33  wait_for_you  阅读(242)  评论(0)  编辑  收藏  举报

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