HDUOJ - 1316 How Many Fibs?
How Many Fibs?
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4592 Accepted Submission(s): 1803
Problem Description
Recall the definition of the Fibonacci numbers:
f1 := 1
f2 := 2
fn := fn-1 + fn-2 (n >= 3)
Given two numbers a and b, calculate how many Fibonacci numbers are in the range [a, b].
f1 := 1
f2 := 2
fn := fn-1 + fn-2 (n >= 3)
Given two numbers a and b, calculate how many Fibonacci numbers are in the range [a, b].
Input
The input contains several test cases. Each test case consists of two non-negative integer numbers a and b. Input is terminated by a = b = 0. Otherwise, a <= b <= 10^100. The numbers a and b are given with no superfluous leading zeros.
Output
For each test case output on a single line the number of Fibonacci numbers fi with a <= fi <= b.
Sample Input
10 100 1234567890 9876543210 0 0
Sample Output
5 4import java.io.*; import java.math.*; import java.text.*; import java.util.*; public class Main { public static void main(String[] args) { Scanner cin = new Scanner(System.in); BigInteger []Fib = new BigInteger[1024]; Fib[0] = Fib[1] = BigInteger.valueOf(1); for(int i = 2; i < 1024; i++) Fib[i] = Fib[i-1].add(Fib[i-2]); while(cin.hasNextBigInteger()){ BigInteger l = cin.nextBigInteger(); BigInteger r = cin.nextBigInteger(); int cnt = 0; if(l.compareTo(BigInteger.ZERO)==0 && r.compareTo(BigInteger.ZERO)==0) return ; if(l.compareTo(r) > 0){ BigInteger t = l; l = r; r = t; } for(int i = 1; i < 1024; i++) if(Fib[i].compareTo(l)>=0 && Fib[i].compareTo(r)<=0) cnt++; System.out.println(cnt); } } }