【学习笔记】linq与lambda写法对照
linq与lambda写法对照
SQL | LINQ | Lambda |
SELECT * FROM Employee | from e in Employees select e | Employees.Select () |
SELECT e.LoginID,e.JobTitle FROM Employee AS e | from e in Employees select new {e.LoginID, e.JobTitle} | Employees.Select ( e => new{LoginID = e.LoginID,JobTitle = e.JobTitle} ) |
SELECT e.LoginID AS ID, e.JobTitle AS Title FROM Employee AS e | from e in Employees select new {ID = e.LoginID, Title = e.JobTitle} | Employees.Select (e => new{ID = e.LoginID,Title = e.JobTitle } ) |
SELECT DISTINCT e.JobTitle FROM Employee AS e | (from e in Employees select e.JobTitle).Distinct() | Employees.Select (e => e.JobTitle) .Distinct () |
SELECT e.* FROM Employee AS e WHERE e.LoginID = ‘test’ | from e in Employees where e.LoginID == “test” select e | Employees.Where (e => (e.LoginID == “test”)) |
SELECT e.* FROM Employee AS e WHERE e.LoginID = ‘test’ AND e.SalariedFlag = 1 | from e in Employees where e.LoginID == “test” && e.SalariedFlag select e | Employees.Where (e => ((e.LoginID == “test”) && e.SalariedFlag)) |
SELECT e.* FROM Employee AS e WHERE e.VacationHours >= 2 AND e.VacationHours <= 10 | from e in Employees where e.VacationHours >= 2 && e.VacationHours <= 10 select e | Employees.Where (e => (((Int32)(e.VacationHours) >= 2) && ((Int32)(e.VacationHours) <= 10))) |
SELECT e.* FROM Employee AS e ORDER BY e.NationalIDNumber | from e in Employees orderby e.NationalIDNumber select e | Employees.OrderBy (e => e.NationalIDNumber) |
SELECT e.* FROM Employee AS e ORDER BY e.HireDate DESC, e.NationalIDNumber | from e in Employees orderby e.HireDate descending, e.NationalIDNumber select e | Employees.OrderByDescending (e => e.HireDate).ThenBy (e => e.NationalIDNumber) |
SELECT e.* FROM Employee AS e WHERE e.JobTitle LIKE ‘Vice%’ OR SUBSTRING(e.JobTitle, 0, 3) = ‘Pro’ | from e in Employees where e.JobTitle.StartsWith(“Vice”) || e.JobTitle.Substring(0, 3) == “Pro” select e | Employees.Where (e => (e.JobTitle.StartsWith (“Vice”) || (e.JobTitle.Substring (0, 3) == “Pro”))) |
SELECT SUM(e.VacationHours) FROM Employee AS e | Employees.Sum(e => e.VacationHours); | |
SELECT COUNT(*) FROM Employee AS e | Employees.Count(); | |
SELECT SUM(e.VacationHours) AS TotalVacations,e.JobTitle FROM Employee AS e GROUP BY e.JobTitle | from e in Employees group e by e.JobTitle into g select new {JobTitle = g.Key, TotalVacations = g.Sum(e => e.VacationHours)} | Employees.GroupBy (e => e.JobTitle) .Select (g =>new{JobTitle = g.Key, TotalVacations = g.Sum (e => (Int32)(e.VacationHours)) }) |
SELECT e.JobTitle, SUM(e.VacationHours) AS TotalVacations FROM Employee AS e GROUP BY e.JobTitle HAVING e.COUNT(*) > 2 | from e in Employees group e by e.JobTitle into g where g.Count() > 2 select new {JobTitle = g.Key, TotalVacations = g.Sum(e => e.VacationHours)} | Employees.GroupBy (e => e.JobTitle) .Where (g => (g.Count () > 2)).Select ( g =>new{JobTitle = g.Key, TotalVacations = g.Sum (e => (Int32)(e.VacationHours))} ) |
SELECT * FROM Product AS p,ProductReview AS pr | from p in Products from pr in ProductReviews select new {p, pr} | Products.SelectMany (p => ProductReviews,(p, pr) =>new{ p = p, pr = pr}) |
SELECT * FROM Product AS p INNER JOIN ProductReview AS pr ON p.ProductID = pr.ProductID | from p in Products join pr in ProductReviews on p.ProductID equals pr.ProductID select new {p, pr} | Products.Join (ProductReviews, p => p.ProductID,pr => pr.ProductID, (p, pr) =>new{p = p,pr = pr}) |
SELECT * FROM Product AS p INNER JOIN ProductCostHistory AS pch ON p.ProductID = pch.ProductID AND p.SellStartDate = pch.StartDate | from p in Products join pch in ProductCostHistories on new {p.ProductID, StartDate = p.SellStartDate} equals new {pch.ProductID, StartDate = pch.StartDate}select new {p, pch} | Products.Join (ProductCostHistories, p =>new{ProductID = p.ProductID, StartDate = p.SellStartDate}, pch =>new{ProductID = pch.ProductID, StartDate = pch.StartDate}, (p, pch) =>new{p = p,pch = pch}) |
SELECT * FROM Product AS p LEFT OUTER JOIN ProductReview AS pr ON p.ProductID = pr.ProductID | from p in Products join pr in ProductReviews on p.ProductID equals pr.ProductID into prodrev select new {p, prodrev} | Products.GroupJoin (ProductReviews, p => p.ProductID,pr => pr.ProductID,(p, prodrev) => new{p = p,prodrev = prodrev }) |
SELECT p.ProductID AS ID FROM Product AS p UNION SELECT pr.ProductReviewID FROM ProductReview AS pr | (from p in Products select new {ID = p.ProductID}).Union(from pr in ProductReviews select new {ID = pr.ProductReviewID}) | Products.Select (p => new{ID =p.ProductID}).Union (ProductReviews .Select (pr =>new{ ID = pr.ProductReviewID})) |
SELECT TOP (10) * FROM Product AS p WHERE p.StandardCost < 100 | (from p in Products where p.StandardCost < 100 select p).Take(10) | Products.Where (p => (p.StandardCost < 100)).Take (10) |
SELECT * FROM [Product] AS p WHERE p.ProductID IN (SELECT pr.ProductID FROM [ProductReview] AS [pr] WHERE pr.[Rating] = 5) | from p in Products where (from pr in ProductReviews where pr.Rating == 5 select pr.ProductID).Contains(p.ProductID)select p | Products.Where (p =>ProductReviews.Where (pr => (pr.Rating == 5)) .Select (pr => pr.ProductID).Contains (p.ProductID) |