摘要：统计同成绩学生人数Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7066Accepted Submission(s): 4118Problem Description读入N名学生的成绩，将获得某一给定分数的学生人数输出。Input测试输入包含若干测试用例，每个测试用例的格式为第1行：N第2行：N名学生的成绩，相邻两数字用一个空格间隔。第3行：给定分数当读到N=0时输入结束。其中N不超过1000，成绩分数为（包含）0到100之间的一个整数。Ou
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摘要：开门人和关门人Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5372Accepted Submission(s): 2773Problem Description每天第一个到机房的人要把门打开，最后一个离开的人要把门关好。现有一堆杂乱的机房签 到、签离记录，请根据记录找出当天开门和关门的人。 Input测试输入的第一行给出记录的总天数N ( > 0 )。下面列出了N天的记录。 每天的记录在第一行给出记录的条目数M ( > 0 )，
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摘要：题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=1219简单题。收获：gets()的使用。AC MeTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5280Accepted Submission(s): 2388Problem DescriptionIgnatius is doing his homework now. The teacher gives him some articles and
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摘要：吃糖果Time Limit: 6000/3000 MS (Java/Others)Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 6890Accepted Submission(s): 1997Problem DescriptionHOHO，终于从Speakless手上赢走了所有的糖果，是Gardon吃糖果时有个特殊的癖好，就是不喜欢将一样的糖果放在一起吃，喜欢先吃一种，下一次吃另一种，这样；可是Gardon不知道是否存在一种吃糖果的顺序使得他能把所有糖果都吃完？请你写个程序帮忙计算一下。Input第一行有一个整数T，
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摘要：The calculation of GPATime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9186Accepted Submission(s): 2110Problem Description每学期的期末，大家都会忙于计算自己的平均成绩，这个成绩对于评奖学金是直接有关的。国外大学都是计算GPA(grade point average) 又称GPR(grade point ratio)，即成绩点数与学分的加权平均值来代表一个学生的成绩的。那么如
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摘要：18岁生日Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7131Accepted Submission(s): 2209Problem DescriptionGardon的18岁生日就要到了，他当然很开心，可是他突然想到一个问题，是不是每个人从出生开始，到达18岁生日时所经过的天数都是一样的呢？似乎并不全都是这样，所以他想请你帮忙计算一下他和他的几个朋友从出生到达18岁生日所经过的总天数，让他好来比较一下。Input一个数T，后面T行每行有一
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摘要：Specialized Four-Digit NumbersTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1431Accepted Submission(s): 1017Problem DescriptionFind and list all four-digit numbers in decimal notation that have the property that the sum of its four digits equals
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摘要：Lowest BitTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3399Accepted Submission(s): 2426Problem DescriptionGiven an positive integer A (1 <= A <= 100), output the lowest bit of A.For example, given A = 26, we can write A in binary form as 1
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摘要：Beat the Spread!Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1723Accepted Submission(s): 899Problem DescriptionSuperbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local
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摘要：http://poj.org/problem?id=2109Power of CryptographyTime Limit: 1000MSMemory Limit: 30000KTotal Submissions: 10904Accepted: 5626DescriptionCurrent work in cryptography involves (among other things) large prime numbers and computing powers of numbers among these primes. Work in this area has resulted
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摘要：MilkTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5689Accepted Submission(s): 1291Problem DescriptionIgnatius drinks milk everyday, now he is in the supermarket and he wants to choose a bottle of milk. There are many kinds of milk in the supermar
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摘要：排序Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 15676Accepted Submission(s): 4032Problem Description输入一行数字，如果我们把这行数字中的‘5’都看成空格，那么就得到一行用空格分割的若干非负整数（可能有些整数以‘0’开头，这些头部的‘0’应该被忽略掉，除非这个整数就是由若干个‘0’组成的，这时这个整数就是0）。你的任务是：对这些分割得到的整数，依从小到大的顺序排序输出。Input输入包含多组
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摘要：最小公倍数Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 14564Accepted Submission(s): 7651Problem Description给定两个正整数，计算这两个数的最小公倍数。Input输入包含多组测试数据，每组只有一行，包括两个不大于1000的正整数.Output对于每个测试用例，给出这两个数的最小公倍数，每个实例输出一行。Sample Input10 14Sample Output70SourcePOJ Reco
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摘要：Who's in the MiddleTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3360Accepted Submission(s): 1646Problem DescriptionFJ is surveying his herd to find the most average cow. He wants to know how much milk this 'median' cow gives: half of
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摘要：Eddy's digital RootsTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1609Accepted Submission(s): 947Problem DescriptionThe digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit
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摘要：Eddy's research ITime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2443Accepted Submission(s): 1492Problem DescriptionEddy's interest is very extensive, recently he is interested in prime number. Eddy discover the all number owned can be divi
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摘要：Balloon Comes!Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 10546Accepted Submission(s): 3623Problem DescriptionThe contest starts now! How excited it is to see balloons floating around. You, one of the best programmers in HDU, can get a very bea
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摘要：Ignatius's puzzleTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2716Accepted Submission(s): 1788Problem DescriptionIgnatius is poor at math,he falls across a puzzle problem,so he has no choice but to appeal to Eddy. this problem describes that
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摘要：A hard puzzleTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13437Accepted Submission(s): 4677Problem Descriptionlcy gives a hard puzzle to feng5166,lwg,JGShining and Ignatius: gave a and b,how to know the a^b.everybody objects to this BT problem,s
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摘要：Humble NumbersTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6085Accepted Submission(s): 2639Problem DescriptionA number whose only prime factors are 2,3,5 or 7 is called a humble number. The sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 14, 15, 16,
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