Rightmost Digit ACM HDU1061

Rightmost Digit

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 12357    Accepted Submission(s): 4773

Problem Description

Given a positive integer N, you should output the most right digit of N^N.

 

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single positive integer N(1<=N<=1,000,000,000).

 

Output

For each test case, you should output the rightmost digit of N^N.

 

Sample Input

2 3 4

 

Sample Output

7 6

Hint

In the first case, 3 * 3 * 3 = 27, so the rightmost digit is 7. In the second case, 4 * 4 * 4 * 4 = 256, so the rightmost digit is 6.

 

Author

Ignatius.L

 

主要掌握模幂运算，而且求个位，一直求10的模

#include<stdio.h>
#include<iostream>
using namespace std;
int solve(long long n)
{
    int t,b;
    long long i;
    b=n%10;
    t=1;
    if(b==0)return 0;
    while(n)
    {
        if(n%2==1)
        {
            t*=b;
            t%=10;
        } 
        b*=b;
        b%=10;
        n/=2; 
          
    }    
    return t;  
}
int main()
{
    int T;
    long long n;
    cin>>T;
    while(T--)
    {
        cin>>n;
        cout<<solve(n)<<endl;
    }   
    return 0; 
}