ACM HDU 1012

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 12753    Accepted Submission(s): 5485

Problem Description

A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

 

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

 

Sample Output

n e - ----------- 0 1 1 2 2 2.5 3 2.666666667 4 2.708333333

 

Source

Greater New York 2000

 

Recommend

JGShining

 

水题，太简单

#include<stdio.h>
#include<iostream>
using namespace std;
int main()
{
    int i;
    double  e=2.5;
    double  a=0.5;
    printf("n e\n- -----------\n0 1\n1 2\n2 2.5\n");
    for(i=3;i<=9;i++)
    {
        a=a/i;
        e+=a;
        printf("%d %.9lf\n",i,e);
    }   
    //system("pause"); 
    return 0;
}