poj 1007 DNA sorting (qsort)
DNA Sorting
Time Limit: 1000MS | Memory Limit: 10000K | |
Total Submissions: 95209 | Accepted: 38311 |
Description
One measure of ``unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For instance, in the letter sequence ``DAABEC'', this measure is 5, since D is greater than four letters to its right and E is greater than one letter to its right. This measure is called the number of inversions in the sequence. The sequence ``AACEDGG'' has only one inversion (E and D)---it is nearly sorted---while the sequence ``ZWQM'' has 6 inversions (it is as unsorted as can be---exactly the reverse of sorted).
You are responsible for cataloguing a sequence of DNA strings (sequences containing only the four letters A, C, G, and T). However, you want to catalog them, not in alphabetical order, but rather in order of ``sortedness'', from ``most sorted'' to ``least sorted''. All the strings are of the same length.
You are responsible for cataloguing a sequence of DNA strings (sequences containing only the four letters A, C, G, and T). However, you want to catalog them, not in alphabetical order, but rather in order of ``sortedness'', from ``most sorted'' to ``least sorted''. All the strings are of the same length.
Input
The first line contains two integers: a positive integer n (0 < n <= 50) giving the length of the strings; and a positive integer m (0 < m <= 100) giving the number of strings. These are followed by m lines, each containing a string of length n.
Output
Output the list of input strings, arranged from ``most sorted'' to ``least sorted''. Since two strings can be equally sorted, then output them according to the orginal order.
Sample Input
10 6 AACATGAAGG TTTTGGCCAA TTTGGCCAAA GATCAGATTT CCCGGGGGGA ATCGATGCAT
Sample Output
CCCGGGGGGA AACATGAAGG GATCAGATTT ATCGATGCAT TTTTGGCCAA TTTGGCCAAA
C/C++代码
#include <stdio.h> #include <string.h> #include <stdlib.h> struct Str{ char str[51]; int inversions; }data[100]; int inversionNumber(char s[]) { int len = strlen(s); int result = 0; int A = 0, C = 0, G = 0; int i = len - 1; for(; i >= 0; i--) switch (s[i]) { case 'A': A++; break; case 'C': result += A; C++; break; case 'G': result = result + A + C; G++; break; case 'T': result = result + A + C + G; break; } return result; } int cmp(const void * a, const void * b) { struct Str* c = (struct Str *)a; struct Str* d = (struct Str *)b; return c->inversions - d->inversions; } int main(int argc, const char * argv[]) { int length, number; int i; scanf("%d%d", &length, &number); for (i = 0; i < number; i ++) { scanf("%s", data[i].str); data[i].inversions = inversionNumber(data[i].str); } qsort(data, number, sizeof(data[0]), cmp); for (i = 0; i < number; i ++) { printf("%s\n", data[i].str); } return 0; }