[lintcode easy]Longest Increasing Continuous subsequence

Longest Increasing Continuous subsequence

 

Give you an integer array (index from 0 to n-1, where n is the size of this array),find the longest increasing continuous subsequence in this array. (The definition of the longest increasing continuous subsequence here can be from right to left or from left to right)

Example

For [5, 4, 2, 1, 3], the LICS is [5, 4, 2, 1], return 4.

For [5, 1, 2, 3, 4], the LICS is [1, 2, 3, 4], return 4.

Note

O(n) time and O(1) extra space.

 

public class Solution {
    /**
     * @param A an array of Integer
     * @return  an integer
     */
    public int longestIncreasingContinuousSubsequence(int[] A) {
        // Write your code here
        
        if(A.length==0) return 0;
        int count=2;
        int maxCount=1;
        
        
        for(int i=1;i<A.length-1;i++)
        {
            if(A[i]>A[i+1] && A[i-1]>A[i] )
            {
                count++;
                maxCount=Math.max(maxCount,count);
                
            }
            else if(A[i]<A[i+1]&&A[i-1]<A[i])
            {
                count++;
                maxCount=Math.max(maxCount,count);
            }
            else
            {
                count=2;
            }
            
            
        }
        
        return maxCount;
    }
}

 

posted on 2015-12-01 05:14  一心一念  阅读(143)  评论(0编辑  收藏  举报

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