[HDOJ2444]The Accomodation of Students(二分图染色判定,最大匹配,匈牙利算法)

题目链接:http://acm.split.hdu.edu.cn/showproblem.php?pid=2444

题意:求这个图是否是二分图,如果是则求最大匹配。

数据就是图,kuangbin的匈牙利算法板子。

 

  1 /*
  2 ━━━━━┒ギリギリ♂ eye!
  3 ┓┏┓┏┓┃キリキリ♂ mind!
  4 ┛┗┛┗┛┃\○/
  5 ┓┏┓┏┓┃ /
  6 ┛┗┛┗┛┃ノ)
  7 ┓┏┓┏┓┃
  8 ┛┗┛┗┛┃
  9 ┓┏┓┏┓┃
 10 ┛┗┛┗┛┃
 11 ┓┏┓┏┓┃
 12 ┛┗┛┗┛┃
 13 ┓┏┓┏┓┃
 14 ┃┃┃┃┃┃
 15 ┻┻┻┻┻┻
 16 */
 17 #include <algorithm>
 18 #include <iostream>
 19 #include <iomanip>
 20 #include <cstring>
 21 #include <climits>
 22 #include <complex>
 23 #include <fstream>
 24 #include <cassert>
 25 #include <cstdio>
 26 #include <bitset>
 27 #include <vector>
 28 #include <deque>
 29 #include <queue>
 30 #include <stack>
 31 #include <ctime>
 32 #include <set>
 33 #include <map>
 34 #include <cmath>
 35 using namespace std;
 36 #define fr first
 37 #define sc second
 38 #define cl clear
 39 #define BUG puts("here!!!")
 40 #define W(a) while(a--)
 41 #define pb(a) push_back(a)
 42 #define Rint(a) scanf("%d", &a)
 43 #define Rll(a) scanf("%I64d", &a)
 44 #define Rs(a) scanf("%s", a)
 45 #define Cin(a) cin >> a
 46 #define FRead() freopen("in", "r", stdin)
 47 #define FWrite() freopen("out", "w", stdout)
 48 #define Rep(i, len) for(int i = 0; i < (len); i++)
 49 #define For(i, a, len) for(int i = (a); i < (len); i++)
 50 #define Cls(a) memset((a), 0, sizeof(a))
 51 #define Clr(a, x) memset((a), (x), sizeof(a))
 52 #define Full(a) memset((a), 0x7f7f7f, sizeof(a))
 53 #define lrt rt << 1
 54 #define rrt rt << 1 | 1
 55 #define pi 3.14159265359
 56 #define RT return
 57 #define lowbit(x) x & (-x)
 58 #define onecnt(x) __builtin_popcount(x)
 59 typedef long long LL;
 60 typedef long double LD;
 61 typedef unsigned long long ULL;
 62 typedef pair<int, int> pii;
 63 typedef pair<string, int> psi;
 64 typedef pair<LL, LL> pll;
 65 typedef map<string, int> msi;
 66 typedef vector<int> vi;
 67 typedef vector<LL> vl;
 68 typedef vector<vl> vvl;
 69 typedef vector<bool> vb;
 70 
 71 typedef struct Edge {
 72     int u, v;
 73     int next;
 74 }Edge;
 75 
 76 const int maxn = 220;
 77 const int maxm = maxn*maxn;
 78 int n, m, ecnt;
 79 int color[maxn];
 80 int head[maxn];
 81 Edge edge[maxm];
 82 int q[maxm], front, tail;
 83 
 84 void init() {
 85     ecnt = 0;
 86     Clr(head, -1); Clr(color, -1);
 87 }
 88 void adde(int u, int v) {
 89     edge[ecnt].u = u;
 90     edge[ecnt].v = v;
 91     edge[ecnt].next = head[u];
 92     head[u] = ecnt++;
 93 }
 94 
 95 bool bfs(int u) {
 96     front = tail = 0;
 97     color[u] = 0;
 98     q[tail++] = u;
 99     int p = -1;
100     while(front < tail) {
101         int t = q[front++];
102         for(int i = head[t]; ~i; i=edge[i].next) {
103             int v = edge[i].v;
104             if(v == t) continue;
105             if(color[v] == -1) {
106                 color[v] = 1 ^ color[t];
107                 q[tail++] = v;
108             }
109             else if(color[v] == color[t]) return 0;
110         }
111     }
112     return 1;
113 }
114 
115 int nu,nv;//u,v的数目,使用前面必须赋值
116 int G[maxn][maxn];//邻接矩阵
117 int linker[maxn];
118 bool used[maxn];
119 
120 bool dfs(int u) {
121     for(int v = 0; v < nv;v++)
122     if(G[u][v] && !used[v]) {
123         used[v] = true;
124         if(linker[v] == -1 || dfs(linker[v])) {
125             linker[v] = u;
126             return true;
127         }
128     }
129     return false;
130 }
131 
132 int hungary() {
133     int ret = 0;
134     memset(linker, -1, sizeof(linker));
135     for(int u = 0; u < nu; u++) {
136         memset(used, 0, sizeof(used));
137         if(dfs(u)) ret++;
138     }
139     return ret;
140 }
141 
142 int main() {
143     // FRead();
144     int u, v;
145     while(~Rint(n) && ~Rint(m)) {
146         init(); Cls(G);
147         Rep(i, m) {
148             Rint(u); Rint(v);
149             adde(u, v); adde(v, u);
150             G[u-1][v-1] = G[v-1][u-1] = 1;
151         }
152         bool exflag = 0;
153         For(i, 1, n+1) {
154             if(color[i] == -1) {
155                 if(bfs(i) == 0) {
156                     exflag = 1;
157                     break;
158                 }
159             }
160         }
161         if(exflag) {
162             printf("No\n");
163             continue;
164         }
165         nu = nv = n;
166         printf("%d\n", hungary()/2);
167     }
168     RT 0;
169 }

 

posted @ 2016-08-24 16:58  Kirai  阅读(150)  评论(0编辑  收藏  举报