7-7 sdut-oop-7 答答租车系统（类的继承与多态 面向对象综合练习）- -python

写了很多冗余数据：车型名称可以不要

class Che:
    id=0
    name='A'
    maxpeo=0
    weight=0
    meo=0
    def __init__(self,id,name,maxpeo,weight,meo):
        self.id=id
        self.name=name
        self.maxpeo=maxpeo
        self.meo=meo
        self.weight=weight
    def getMaxpeo(self,n):
        return self.maxpeo*n
    def getWeight(self,n):
        return self.weight*n
    def getMeo(self,n):
        return self.meo*n    
class KeChe(Che):
    def __init__(self,id,name,maxpeo,meo):
        self.id=id
        self.name=name
        self.maxpeo=maxpeo
        self.meo=meo
    
class HuoChe(Che):
    def __init__(self,id,name,weight,meo):
        self.id=id
        self.name=name
        self.weight=weight
        self.meo=meo

ans=[]
ans.append(KeChe(1,"d",5,800))
ans.append(KeChe(2,"d",5,400))
ans.append(KeChe(3,"d",5,800))
ans.append(KeChe(4,"d",51,1300))
ans.append(KeChe(5,"d",55,1500))
ans.append(Che(6,"d",5,0.45,500))
ans.append(Che(7,"d",5,2.0,450))
ans.append(HuoChe(8,"d",3,200))
ans.append(HuoChe(9,"d",25,1500))
ans.append(HuoChe(10,"d",35,2000))
x=int(input())
if x==1:
    n=int(input())
    sum1=0.0
    sum2=0.0
    sum3=0.0
    for i in range(n):
        #a表示要租车的编号，
        #b表示租用该车型的天数。
        a,b=map(int,input().split())
        sum1+=ans[a-1].getMaxpeo(b)
        sum2+=ans[a-1].getWeight(b)
        sum3+=ans[a-1].getMeo(b)
    print(int(sum1),'%.2f' %sum2,int(sum3))
else:
    print("0 0.00 0")