写了一个时间处理的类,能将人类时间转换成距离公元零年一月一日秒数(时间戳),同时支持时间戳转换成日期时间
1 #include "stdafx.h" 2 #include <stdlib.h> 3 #include <string.h> 4 #include <time.h> 5 6 #define IS_LEAP_YEAR(y) (((y) % 4 == 0 && (y) % 100 != 0) || (y) % 400 == 0) 7 8 #define if_not_eual_ret(left, right) do {\ 9 if (left < right) {return true;} else if(left > right) {return false;}\ 10 } while(0) 11 12 //从网上抄的 计算日期相差天数的函数 13 int day_diff(int year_start, int month_start, int day_start, 14 int year_end, int month_end, int day_end) 15 { 16 int y2, m2, d2; 17 int y1, m1, d1; 18 19 m1 = (month_start + 9) % 12; 20 y1 = year_start - m1/10; 21 d1 = 365*y1 + y1/4 - y1/100 + y1/400 + (m1*306 + 5)/10 + (day_start - 1); 22 23 m2 = (month_end + 9) % 12; 24 y2 = year_end - m2/10; 25 d2 = 365*y2 + y2/4 - y2/100 + y2/400 + (m2*306 + 5)/10 + (day_end - 1); 26 27 return (d2 - d1); 28 } 29 30 31 class CMyDateTime 32 { 33 public: 34 CMyDateTime(int sec_from_beg = 0) 35 { 36 m_sec_from_beg = sec_from_beg; 37 } 38 39 CMyDateTime(int year, int month, int day, int hour, int minute, int second) 40 { 41 m_sec_from_beg = to_second(year, month, day, hour, minute, second); 42 } 43 44 bool operator < (const CMyDateTime& theDate) 45 { 46 return m_sec_from_beg < theDate.m_sec_from_beg; 47 } 48 49 //获得0001 01:01:00至当前时间秒数 50 long long to_second() 51 { 52 return m_sec_from_beg; 53 } 54 55 56 //年 取1900-3000 月 取0-11 日 取1-31 时分秒 取0-59 57 static long long to_second(int year, int month, int day, int hour, int minute, int second) 58 { 59 //获取当前日期至纪元1年的天数 60 int y1 = year, m1 = 0, d1 = day - 1; 61 long long sec; 62 63 //每月天数 64 int month_day[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; 65 66 if (IS_LEAP_YEAR(year)) 67 { 68 month_day[1]++; 69 } 70 for (int i = 0; i < month; i++) 71 { 72 m1 += month_day[i]; 73 } 74 75 y1 -= 1; 76 d1 = 365*y1 + y1/4 - y1/100 + y1/400 + m1 + d1; 77 78 //24小时 60分 60秒 79 sec = (long long)d1 * (24 * 60 * 60); 80 sec += hour * 3600 + minute * 60 + second; 81 return sec; 82 } 83 84 //把秒数转换成标准日期 85 bool to_date(int& year, int& month, int& day, int& hour, int& minute, int& second) 86 { 87 // 先计算大概年份,用秒数除以366天秒数 88 int day_from_beg = (int)(m_sec_from_beg / (24 * 60 * 60)); 89 90 int second_left = int(m_sec_from_beg - day_from_beg * (long long) (24 * 60 * 60)); 91 hour = second_left / (60 * 60); 92 93 second_left = int (second_left - hour * (60 * 60)); 94 minute = second_left / 60; 95 second = second_left % 60; 96 97 int year_cnt = day_from_beg / 366; 98 //每年365天 闰年多一天 99 int day_from_beg_to_year = (year_cnt * 365 + year_cnt / 4 - year_cnt / 100 + year_cnt / 400); 100 101 //然后逐年累加天数,直到天数大于day_from_beg 102 while (day_from_beg_to_year <= day_from_beg) 103 { 104 if (IS_LEAP_YEAR(year_cnt + 1)) 105 { 106 day_from_beg_to_year += 366; 107 } 108 else 109 { 110 day_from_beg_to_year += 365; 111 } 112 year_cnt++; 113 } 114 //因为是要取最后一个小于等于在数 所以在这里要减一 115 year_cnt--; 116 117 //知道年份后,再计算月份 先计算出当前日期距离今年开始相差多少天 118 int day_from_year = day_from_beg - (year_cnt * 365 + year_cnt / 4 - year_cnt / 100 + year_cnt / 400); 119 //今年的年数 = 经过的年数 + 1 120 year = year_cnt + 1; 121 122 //每月天数 123 int month_day[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; 124 125 if (IS_LEAP_YEAR(year)) 126 { 127 month_day[1]++; 128 } 129 130 for (month = 0; month < 12; month++) 131 { 132 if ((day_from_year - month_day[month]) < 0) 133 { 134 break; 135 } 136 137 day_from_year -= month_day[month]; 138 } 139 day = day_from_year + 1; 140 return true; 141 } 142 private: 143 //当前日期至纪元1年的秒数 144 long long m_sec_from_beg; 145 }; 146 147 //测试函数,测试每一秒钟从人类日期格式转换成CMyDateTime 再转换回来是否正确 148 void test_time() 149 { 150 int month_day[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; 151 152 for (int year = 1; year < 2100; year++) 153 { 154 double start = GetTickCount(); 155 bool is_leap = IS_LEAP_YEAR(year); 156 if (is_leap) 157 { 158 month_day[1] = 29; 159 } 160 161 for (int month = 0; month < 12; month++) 162 { 163 for (int day = 1; day <= month_day[month]; day++) 164 { 165 for (int hour = 0; hour < 24; hour++) 166 { 167 for (int minute = 0; minute < 60; minute++) 168 { 169 for (int second = 0; second < 60; second++) 170 { 171 CMyDateTime t(year, month, day, hour, minute, second); 172 int year_new, month_new, day_new, hour_new, minute_new, second_new; 173 if (t.to_date(year_new, month_new, day_new, hour_new, minute_new, second_new)) 174 { 175 if (year != year_new || month != month_new || day_new != day || 176 hour != hour_new || minute != minute_new || second != second_new) 177 { 178 printf("day = %d day_new = %d\n", day, day_new); 179 printf("month = %d month_new = %d\n", month, month_new); 180 printf("year = %d year_new = %d\n", year, year_new); 181 182 183 printf("hour = %d hour_new = %d\n", hour, hour_new); 184 printf("minute = %d minute_new = %d\n", minute, minute_new); 185 printf("second = %d second_new = %d\n", second, second_new); 186 printf("------------------------\n"); 187 } 188 } 189 } 190 } 191 } 192 } 193 } 194 195 if (is_leap) 196 { 197 month_day[1] = 28; 198 } 199 200 //我的机器一年花5秒左右 效率不是特别高 但目前没有优化头绪 201 printf("总共耗时 %f 毫秒\n", GetTickCount() - start); 202 printf("------------[%04d]------------\n", year); 203 } 204 }
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