欧拉计划 第6题

The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

 

long sumOfSquares = 0;
           for (int i = 1; i <= 100; i++)
           {
               sumOfSquares += (long)Math.Pow(i, 2);
           }
 
           long sum = 0;
           for (int i = 1; i <= 100; i++)
           {
               sum += i;
           }
           long squaresOfSum = (long)Math.Pow(sum,2);
           Console.WriteLine("{0}-{1}={2}", squaresOfSum, sumOfSquares, squaresOfSum - sumOfSquares);

 

posted @   kiminozo  阅读(279)  评论(0编辑  收藏  举报
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