欧拉计划 第6题
The sum of the squares of the first ten natural numbers is,
12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
long sumOfSquares = 0; for ( int i = 1; i <= 100; i++) { sumOfSquares += ( long )Math.Pow(i, 2); } long sum = 0; for ( int i = 1; i <= 100; i++) { sum += i; } long squaresOfSum = ( long )Math.Pow(sum,2); Console.WriteLine( "{0}-{1}={2}" , squaresOfSum, sumOfSquares, squaresOfSum - sumOfSquares); |
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