例题 第七章 整。
例题7-1
#include<stdio.h> int main(void) { int count[9]; int i,response; for(i=1;i<=8;i++) count[i]=0; for(i=1;i<=10;i++){ printf("input your response:"); scanf("%d",&response); if(response<1||response>8) printf("this is a bad response: %d\n",response); else count[response]++; } printf("result:\n"); for(i=1;i<=8;i++) printf("%4d%4d\n",i,count[i]); return 0; }
例题7-2
#include<stdio.h> int main(void) { int i; int fib[10]={1,1}; for(i=2;i<10;i++) fib[i]=fib[i-1]+fib[i-2]; for(i=0;i<10;i++){ printf("%6d",fib[i]); if((i+1)%5==0) printf("\n"); } return 0; }
例题7-3
#include<stdio.h> int main(void) { int i,flag,x; int a[5]; printf("Enter 5 integers:"); for(i=0;i<5;i++) scanf("%d",&a[i]); printf("Enter x:"); scanf("%d",&x); flag=0; for(i=0;i<5;i++) if(a[i]==x){ printf("Index is %d\n",i); flag=1; break; } if(flag==0) printf("No Found\n"); return 0; }
例题7-4
#include<stdio.h> int main(void) { int i,index,n; int a[10]; printf("Enter n:"); scanf("%d",&n); printf("Enter %d integers:",n); for(i=0;i<n;i++) scanf("%d",&a[i]); index=0; for(i=1;i<n;i++) if(a[i]<a[index]) index=i; printf("min is %d\tsub is %d\n",a[index],index); return 0; }
例题7-5
#include<stdio.h> int main(void) { int i,index,k,n,temp; int a[10]; printf("Enter n:"); scanf("%d",&n); printf("Enter %d integers:",n); for(i=0;i<n;i++) scanf("%d",&a[i]); for(k=0;k<n-1;k++){ index=k; for(i=k+1;i<n;i++) if(a[i]<a[index]) index=i; temp=a[index]; a[index]=a[k]; a[k]=temp; } printf("After sorted: "); for(i=0;i<n;i++) printf("%d ",a[i]); printf("\n"); return 0; }
例题7-6
#include<stdio.h> int main(void) { int a[10]={1,2,3,4,5,6,7,8,9,10}; int low,high,mid,n=10,x; printf("Enter x: "); scanf("%d",&x); low=0;high=n-1; while(low<=high) { mid=(low+high)/2; if(x==a[mid]) break; else if(x<a[mid]) high=mid-1; else low=mid+1; } if(low<=high) printf("Index is %d\n",mid); else printf("Not Found\n"); return 0; }
例题7-7
#include<stdio.h> int main(void) { int col,i,j,row; int a[3][2]; printf("Enter 6 integers:\n"); for(i=0;i<3;i++) for(j=0;j<2;j++) scanf("%d",&a[i][j]); for(i=0;i<3;i++){ for(j=0;j<2;j++) printf("%4d",a[i][j]); printf("\n"); } row=col=0; for(i=0;i<3;i++) for(j=0;j<2;j++) if(a[i][j]>a[row][col]){ row=i; col=j; } printf("max=a[%d][%d]=%d\n",row,col,a[row][col]); return 0; }
例题7-8
#include<stdio.h> int main(void) { int i,j; int a[3][2]; for(i=0;i<3;i++) for(j=0;j<2;j++) a[i][j]=i+j; for(i=0;i<3;i++){ for(j=0;j<2;j++) printf("%4d",a[i][j]); printf("\n"); } return 0; }
例题7-9
#include<stdio.h> int main(void) { int i,j,n,temp; int a[6][6]; printf("Enter n: "); scanf("%d",&n); for(i=0;i<n;i++) for(j=0;j<n;j++) a[i][j]=i*n+j+1; for(i=0;i<n;i++) for(j=0;j<n;j++) if(i<=j){ temp=a[i][j]; a[i][j]=a[j][i]; a[j][i]=temp; } for(i=0;i<n;i++){ for(j=0;j<n;j++) printf("%4d",a[i][j]); printf("\n"); } return 0; }
例题7-11
#include<stdio.h> int main(void) { int i,n,m; char s[10]; printf("Enter a string: "); i=0; while((s[i]=getchar())!='\n') i++; s[i]='\0'; for(n=0,m=i-1;n<m;n++,m--) if(s[n]!=s[m]) break; if(n>=m) printf("It is a plalindrome\n"); else printf("It is not a plalindrome\n"); return 0; }
例题7-12
#include<stdio.h> int main(void) { int i,number; char str[10]; printf("Enter a string:"); i=0; while((str[i]=getchar())!='\n') i++; str[i]='\0'; number=0; for(i=0;str[i]!='\0';i++) if(str[i]>='0'&& str[i]<='9') number=number*10+str[i]-'0'; printf("digit=%d\n",number); return 0; }
例题7-13
#include<stdio.h> int main(void) { int count,i; char str[80]; printf("Enter a string: "); i=0; while((str[i]=getchar())!='\n') i++; str[i]='\0'; count=0; for(i=0;str[i]!='\0';i++) if(str[i]<='9'&&str[i]>='0') count++; printf("count=%d\n",count); return 0; }
例题7-14
#include<stdio.h> int main(void) { int i,k; char str1[80],str2[80]; long number; printf("Enter a string: "); i=0; while((str1[i]=getchar())!='\n') i++; str1[i]='\0'; k=0; for(i=0;str1[i]!='\0';i++) if (str1[i]>='0'&&str1[i]<='9'||str1[i]>='a'&&str1[i]<='f'||str1[i]>='A'&&str1[i]<='F') { str2[k]=str1[i]; k++; } str2[k]='\0'; number=0; for(i=0;str2[i]!='\0';i++) if(str2[i]>='0'&&str2[i]<='9') number=number*16+str2[i]-'0'; else if(str2[i]>='a'&&str2[i]<='f') number=number*16+str2[i]-'a'+10; else if(str2[i]>='A'&&str2[i]<='F') number=number*16+str2[i]-'A'+10; printf("New string: "); for(i=0;str2[i]!='\0';i++) putchar(str2[i]); printf("\n"); printf("number=%ld\n",number); return 0; }