【leetcode】【21】【合并两个有序链表】

c++

第一个方法

代码

#include <algorithm>
#include <iostream>
#include <memory>
#include <vector>

// Definition for singly-linked list.
struct ListNode {
    int       val;
    ListNode* next;
    ListNode() : val(0), next(nullptr) {}
    ListNode(int x) : val(x), next(nullptr) {}
    ListNode(int x, ListNode* next) : val(x), next(next) {}
};

class Solution {
public:
    ListNode* mergeTwoLists(ListNode* list1, ListNode* list2) {
        if( nullptr == list1){
            return list2;
        }

        if( nullptr == list2){
            return list1;
        }

        // l1 头节点不大于 l2 头结点
        ListNode* l1 = list1;
        ListNode* l2 = list2;
        if (list1->val > list2->val) {
            l1 = list2;
            l2 = list1;
        }

        // 开始插入
        ListNode* cursor = l1;
        while (nullptr != l2) {
            // 去除当前要插入的节点
            ListNode* tmp = l2;
            l2            = l2->next;

            // 找到 l1 中不大于当前插入节点的最后一个节点
            while (nullptr != cursor->next && cursor->next->val <= tmp->val) {
                cursor = cursor->next;
            }
            // 如果已经到 l1 尾部, 直接把 l2 拼接到 l1 后面, 合并结束
            if (nullptr == cursor->next) {
                cursor->next = tmp;
                break;
            }

            // 把当前插入节点追加到 l1 , 并把游标设置为当前插入节点
            tmp->next    = cursor->next;
            cursor->next = tmp;
            cursor       = tmp;
        }

        return l1;
    }
};

static void fill_list(ListNode* list, std::vector<int> data) {
    ListNode* curr = list;
    for (auto i = 0; i < data.size(); i++) {
        curr->val = data[i];
        if (i < data.size() - 1) {
            curr->next = new ListNode();
            curr       = curr->next;
        }
    }
}

static void print_list(ListNode* list) {
    if (nullptr == list) {
        return;
    }
    ListNode* curr = list;
    while (nullptr != curr) {
        std::cout << curr->val << " ";
        curr = curr->next;
    }
    std::cout << std::endl;
}

int main() {
    auto l1 = std::make_unique<ListNode>();
    fill_list(l1.get(), {2, 5, 8});
    print_list(l1.get());

    auto l2 = std::make_unique<ListNode>();
    fill_list(l2.get(), {3, 4, 8, 9});
    print_list(l2.get());

    auto solution = std::make_unique<Solution>();
    auto result   = solution->mergeTwoLists(l1.get(), l2.get());
    print_list(result);

    std::cout << "Hello World!" << std::endl;
}

测试效果

image

java

第一个方法

代码

ListNode.java

package com.laolang.leetcode;

public class ListNode {

    public int val;
    public ListNode next;

    public ListNode() {
    }

    public ListNode(int val) {
        this.val = val;
    }

    public ListNode(int val, ListNode next) {
        this.val = val;
        this.next = next;
    }
}

Solution.java

package com.laolang.leetcode;

import java.util.Objects;

public class Solution {

    public ListNode mergeTwoLists(ListNode list1, ListNode list2) {
        if( Objects.isNull(list1)){
            return list2;
        }

        if( Objects.isNull(list2)){
            return list1;
        }

        ListNode l1 = list1;
        ListNode l2 = list2;
        if(l1.val > l2.val){
            l1 = list2;
            l2 = list1;
        }

        ListNode cursor = l1;
        while( null != l2){
            ListNode tmp = l2;
            l2 = l2.next;

            while( null != cursor.next && cursor.next.val <= tmp.val){
                cursor = cursor.next;
            }

            if( null == cursor.next){
                cursor.next = tmp;
                break;
            }

            tmp.next = cursor.next;
            cursor.next = tmp;
            cursor = tmp;
        }
        return l1;
    }
}

CommonTest.java

package com.laolang.leetcode;

import java.util.List;
import java.util.Objects;
import org.testng.annotations.BeforeClass;
import org.testng.annotations.Test;
import org.testng.collections.Lists;

public class CommonTest {

    private Solution solution;
    private ListNode list1;
    private ListNode list2;


    private void fillList(ListNode list, List<Integer> data){
        ListNode node = list;
        for (int i = 0; i < data.size(); i++) {
            node.val =  data.get(i);
            if( i < data.size() - 1){
                node.next = new ListNode();
                node = node.next;
            }
        }
    }

    @BeforeClass
    public void beforeClass(){
        solution = new Solution();
        list1 = new ListNode();
        list2 = new ListNode();
        fillList(list1, Lists.newArrayList(1,2,3));
        fillList(list2, Lists.newArrayList(1,3,4));
    }

    private void printList(ListNode list){
        if(Objects.isNull(list) ){
            return ;
        }
        ListNode curr = list;
        while( Objects.nonNull(curr)){
            System.out.print(curr.val);
            System.out.print(" ");
            curr = curr.next;
        }
        System.out.println();
    }

    @Test
    public void testOne(){
        printList(list1);
        printList(list2);

        ListNode ret = solution.mergeTwoLists(list1,list2);
        printList(ret);
    }
}

执行效果

image

posted @ 2023-06-30 08:39  laolang2016  阅读(4)  评论(0编辑  收藏  举报