SQL-32 将employees表的所有员工的last_name和first_name拼接起来作为Name,中间以一个空格区分
题目描述
将employees表的所有员工的last_name和first_name拼接起来作为Name,中间以一个空格区分
CREATE TABLE `employees` ( `emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `employees` ( `emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
输入描述:
无
输出描述:
Name |
---|
Facello Georgi |
Simmel Bezalel |
Bamford Parto |
Koblick Chirstian |
Maliniak Kyoichi |
Preusig Anneke |
Zielinski Tzvetan |
Kalloufi Saniya |
Peac Sumant |
Piveteau Duangkaew |
Sluis Mary |
SQL:
select last_name||" "||first_name as Name from employees
使用 || 来进行拼接字符串。