【网络流】 HDU 1569 方格取数(2)

定理:最大点权独立集的点权和=点SUM-最小点权覆盖集的点权和

最小点覆盖=二分图的最大匹配

黑白染色分成一个二分图 

黑色与相连的白色建一条INF的边

源点与黑色建一条边 (容量为点值)

汇点与白色建一条边 (容量为点值)

注意建边

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <string>
#include <iostream>
#include <algorithm>
#include <sstream>
#include <cmath>
using namespace std;
#include <queue>
#include <stack>
#include <vector>
#include <deque>
#include <set>
#include <map>
#include <time.h>;
#define cler(arr, val)    memset(arr, val, sizeof(arr))
#define FOR(i,a,b)  for(int i=a;i<=b;i++)
#define IN   freopen ("in.txt" , "r" , stdin);
#define OUT  freopen ("out.txt" , "w" , stdout);
typedef long long  LL;
const int MAXN = 2503;
const int MAXM = 15006;
const int INF = 0x3f3f3f3f;
const int mod = 10000007;
struct Edge
{
    int to,next,cap,flow;
} edge[MAXM]; //注意是MAXM
int tol;
int head[MAXN];
int gap[MAXN],dep[MAXN],cur[MAXN];
void init()
{
    tol = 0;
    memset(head,-1,sizeof (head));
}
void addedge (int u,int v,int w,int rw = 0)
{
    edge[tol].to = v;
    edge[tol].cap = w;
    edge[tol].flow = 0;
    edge[tol].next = head[u];
    head[u] = tol++;
    edge[tol].to = u;
    edge[tol].cap = rw;
    edge[tol].flow = 0;
    edge[tol].next = head[v];
    head[v] = tol++;
}
int Q[MAXN];
void BFS(int start,int end)
{
    memset(dep,-1,sizeof(dep));
    memset(gap,0,sizeof(gap));
    gap[0] = 1;
    int front = 0, rear = 0;
    dep[end] = 0;
    Q[rear++] = end;
    while(front != rear)
    {
        int u = Q[front++];
        for(int i = head[u]; i !=  -1; i = edge[i].next)
        {
            int v = edge[i]. to;
            if(dep[v] != -1)continue;
            Q[rear++] = v;
            dep[v] = dep[u] + 1;
            gap[dep[v]]++;
        }
    }
}
int S[MAXN];
int sap(int start,int end, int N)
{
    BFS(start,end);
    memcpy(cur,head,sizeof(head));
    int top = 0;
    int u = start;
    int ans = 0;
    int i;
    while(dep[start] < N)
    {
        if(u == end)
        {
            int Min = INF;
            int inser;
            for( i = 0; i < top; i++)
            {
                if(Min > edge[S[i]].cap - edge[S[i]].flow)
                {
                    Min = edge[S[i]].cap - edge[S[i]].flow;
                    inser = i;
                }
            }
            for( i = 0; i < top; i++)
            {
                edge[S[i]]. flow += Min;
                edge[S[i]^1].flow -= Min;
            }
            ans += Min;
            top = inser;
            u = edge[S[top]^1].to;
            continue;
        }
        bool flag =  false;
        int v;
        for( i = cur[u]; i != -1; i = edge[i]. next)
        {
            v = edge[i]. to;
            if(edge[i].cap - edge[i].flow && dep[v]+1 == dep[u])
            {
                flag =  true;
                cur[u] = i;
                break;
            }
        }
        if(flag)
        {
            S[top++] = cur[u];
            u = v;
            continue;
        }
        int Min = N;
        for( i = head[u]; i !=  -1; i = edge[i].next)
        {
            if(edge[i].cap - edge[i].flow && dep[edge[i].to] < Min)
            {
                Min = dep[edge[i].to];
                cur[u] = i;
            }
        }
        gap[dep[u]]--;
        if(!gap[dep[u]]) return ans;
        dep[u] = Min + 1;
        gap[dep[u]]++;
        if(u != start)u = edge[S[--top]^1].to;
    }
    return ans;
}
int n,m;
void addline(int x,int y)
{
    if(x+1<n)
        addedge(x*m+y,(x+1)*m+y,INF);
    if(x-1>=0)
        addedge(x*m+y,(x-1)*m+y,INF);
    if(y+1<m)
        addedge(x*m+y,x*m+y+1,INF);
    if(y-1>=0)
        addedge(x*m+y,x*m+y-1,INF);
}
int main()
{
    //IN;
    while(scanf("%d%d",&n,&m)!=EOF)
    {
        init();
        int sum=0;
        for(int i=0; i<n; i++)
        {
            for(int j=0; j<m; j++)
            {
                int mp;
                scanf("%d",&mp);
                sum+=mp;
                if((i+j)%2)
                {
                    addedge(n*m,i*m+j,mp);
                    addline(i,j);
                }
                else
                    addedge(i*m+j,n*m+1,mp);
            }
        }
        printf("%d\n",sum-sap(n*m,n*m+1,n*m+2));
    }
    return 0;
}


posted @ 2014-09-29 23:48  kewowlo  阅读(156)  评论(0编辑  收藏  举报