1.创建UserDao接口以及UserDaoImpl实现类(接口代码省略)

public class UserDaoImpl implements UserDao {

    private String username;
    private int age;

    public void setUsername(String username) {
        this.username = username;
    }

    public void setAge(int age) {
        this.age = age;
    }

    @Override
    public void save1() {
        System.out.println(username+"======="+age);
        System.out.println("save running...");
    }
}

2.创建UserService接口以及UserServiceImpl实现类(接口代码省略)

public class UserServiceImpl implements UserService {

    private UserDao userDao;

    public UserServiceImpl() {
    }

    public UserServiceImpl(UserDao userDao) {
        this.userDao = userDao;
    }

    @Override
    public void sava() {
        userDao.save1();
    }
}

3.spring配置文件applicationContext.xml的操作

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
       http://www.springframework.org/schema/beans/spring-beans.xsd">

    <bean id="userDao" class="com.hao.dao.impl.UserDaoImpl">
        <property name="username" value="张三"/>
        <property name="age" value="30"/>
    </bean>
    <bean id="userService" class="com.hao.service.impl.UserServiceImpl">
        <constructor-arg name="userDao" ref="userDao"></constructor-arg>
    </bean>
</beans>

4.测试

public class UserController {
    public static void main(String[] args) {
        ApplicationContext context=new ClassPathXmlApplicationContext("applicationContext.xml");
        UserService service = (UserService) context.getBean("userService");
        service.sava();
        
    }
}

结果: 张三=======30
save running…

posted on 2020-11-12 21:35  凸凸大军的一员  阅读(74)  评论(0编辑  收藏  举报