python 写一行代码，计算随机6000次摇筛子，每一个对应出现的次数

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import random   f1 = 0 f2 = 0 f3 = 0 f4 = 0 f5 = 0 f6 = 0 for _ in range(6000):     face = random.randint(1, 6)     if face == 1:         f1 += 1     elif face == 2:         f2 += 1     elif face == 3:         f3 += 1     elif face == 4:         f4 += 1     elif face == 5:         f5 += 1     else:         f6 += 1 print(f'1点出现了{f1}次') print(f'2点出现了{f2}次') print(f'3点出现了{f3}次') print(f'4点出现了{f4}次') print(f'5点出现了{f5}次') print(f'6点出现了{f6}次')