1 #include <stdio.h> 2 3 /* 4 给出一字符串指针，计算出字符串指针中单词数， 5 单词不包括'.',',',';','?','_','"'，由0-9数字或26个字母组成 6 by zww @ 2013.09.26 7 vc 6.0编译通过 8 */ 9 10 unsigned int get_string_word_cnt(const char* pStr) 11 { 12 unsigned int iCnt= 0; 13 unsigned int iCharCnt = 0; 14 const char* p = pStr; 15 16 if (NULL == pStr) 17 { 18 return 0; 19 } 20 21 while ('\0' != *p) 22 { 23 if (('.' == *p) 24 || (',' == *p) 25 || (';' == *p) 26 || ('?' == *p) 27 || (' ' == *p) 28 || ('_' == *p) 29 || ('"' == *p)) 30 { 31 printf("[%c]",*p); 32 iCharCnt=0; 33 } 34 else if (!((*p >= 'a'&& *p<='z') 35 || (*p >='A' && *p<='Z') 36 || (*p >= '0' && *p <='9'))) 37 { 38 printf("[%c]",*p); 39 iCharCnt = 0; 40 } 41 else if (0 == iCharCnt) 42 { 43 iCharCnt++; 44 iCnt++; 45 } 46 47 p++; 48 } 49 50 return iCnt; 51 } 52 53 54 55 int main() 56 { 57 char * str1 = "hello world.1...2"; 58 char * str2 = "hello world.sd,fg!@!$!$!!!!!!!!!!!!hj."; 59 char * str3 = "hello world.fdfg)(*&&&*(hjdfh?>><>,..."; 60 char * str4 = ".hello world.12"; 61 int i = 0; 62 i = get_string_word_cnt(str1); 63 printf(" %d\r\n",i); 64 i = get_string_word_cnt(str2); 65 printf(" %d\r\n",i); 66 i = get_string_word_cnt(str3); 67 printf(" %d\r\n",i); 68 i = get_string_word_cnt(str4); 69 printf(" %d\r\n",i); 70 71 return 0; 72 } 73 74 /** 75 显示结果如下： 76 [ ][.][.][.][.]4 77 [ ][.][,][!][@][!][$][!][$][!][!][!][!][!][!][!][!][!][!][!][!][.]5 78 [ ][.][)][(][*][&][&][&][*][(][?][>][>][<][>][,][.][.][.]4 79 [.][ ][.]3 80 Press any key to continue 81 **/
