获取 文件名中带空格的文件路径

思路：修改 IFS="\n\b"

$1;查找的目录路径

!/bin/bash

SAVEIFS=$IFS
IFS="\n\b"

for file in $(find $1 -maxdepth 1 -iname "*.jpg" -type f )
do
echo file
done

IFS=$SAVEIFS