风言枫语  

最长公共子序列(LCS)问题,dp解决。

要注意每次输出结果后要空行!!!题目的例子上居然没空,害我WA了两次才找到原因 =--=

解题代码如下:

 

#include <iostream>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <algorithm>

using namespace std;
#define max(a,b) ((a)>(b)?(a):(b))
#define maxn 105
int Tower1[maxn], Tower2[maxn];
int N1, N2;
int LongLen[maxn][maxn];
int dp(int i, int j)
{
	if(!i || !j) return 0;
	if(LongLen[i][j]>=0) return LongLen[i][j];
	if(Tower1[i]==Tower2[j]) return LongLen[i][j] = dp(i-1,j-1)+1;
	else return LongLen[i][j] = max( dp(i-1,j), dp(i,j-1));
}
int main()
{
	int Case = 0;
	while(cin >> N1 >> N2 && N1 && N2)
	{
		for(int i=1; i<=N1; i++) cin >> Tower1[i];
		for(int i=1; i<=N2; i++) cin >> Tower2[i];
		memset(LongLen,-1,sizeof(LongLen));
		printf("Twin Towers #%d\nNumber of Tiles : %d\n\n", ++Case, dp(N1,N2));
	}
	return 0;
}


 

 

posted on 2013-08-25 22:08  风言枫语  阅读(215)  评论(0编辑  收藏  举报