快速 读入&&输出 模板

基础版

快速读入

inline void read(int& x) {
  x=0;
  char ch=0;
  bool sign=false;
  while(!isdigit(ch)){ sign|=(ch=='-');ch=getchar();}
  while(isdigit(ch)) { x=x*10+(ch^48); ch=getchar();}
  x=sign?-x:x;
}

快速输出

inline void write(int x) {
  if (x < 0) { putchar('-'); x = -x; }
  if (x > 9) write(x / 10);
  putchar (x % 10+'0');
}

提高版

读入输出一体化的

namespace io {
#define gc() (iS == iT ? (iT = (iS = ibuff) + fread(ibuff, 1, SIZ, stdin), (iS == iT ? EOF : *iS++)) : *iS++)
    const int SIZ = 1 << 21 | 1;
    char *iS, *iT, ibuff[SIZ], obuff[SIZ], *oS = obuff, *oT = oS + SIZ - 1, fu[110], c;
    int fr;
    inline void out() {
        fwrite(obuff, 1, oS - obuff, stdout);
        oS = obuff;
    }
    template<class Type>
    inline void read(Type &x) {
        x = 0;        
        Type y = 1;
        for (c = gc(); (c > '9' || c < '0') && c != '-'; c = gc());
        c == '-' ? y = -1 : x = (c & 15);
        for (c = gc(); c >= '0' && c <= '9'; c = gc())
            x = x * 10 + (c & 15);
        x *= y;
    }
    template<class Type>
    inline void print(Type x, char text = '\n') {
        if (x < 0)
            *oS++ = '-', x *= -1;
        if (x == 0)
            *oS++ = '0';
        while (x)
            fu[++fr] = x % 10 + '0', x /= 10;
        while (fr)
            *oS++ = fu[fr--];
        *oS++ = text;
        out();
    }
}
using namespace io;

一个巨佬写的快读解析

posted @ 2018-10-29 22:55  加固文明幻景  阅读(3)  评论(0编辑  收藏  举报  来源