#include <bits/stdc++.h>
#include<iostream>
#include<algorithm>
#include<cstdio>
#include<vector>
#include<cstring>
#include<cstdlib>
#include<stack>
#include<queue>
#include<string>
#include<stdio.h>
#include<map>
#define IOS ios::sync_with_stdio(false)
using namespace std;
const int maxn=1e6+10;
typedef long long ll;
typedef unsigned long long ull;
struct Node{
double x,y;
double val;
double dis;
Node(){}
Node(int x_,int y_){
x=x_;y=y_;
}
Node operator - (const Node &p){
return Node(x-p.x,y-p.y);
}
double operator ^ (const Node &p){
return x*p.y-y*p.x;
}
}node[1010];
double cross(double x1,double y1,double x2,double y2){
return x1*y2-x2*y1;
}
double cmp(Node a,Node b){
Node c;c.x=0,c.y=0;
double ans = (a-c)^(b-c);
return ans>0;
}
int cmp1 (Node a,Node b){
if(a.val==b.val){
return a.dis>b.dis;
}
return a.val<b.val;
}
double PI = acos(-1.0);
int main(){
int t;
int cas=0;
scanf("%d",&t);
while(t--){
int n;scanf("%d",&n);
for(int i=0;i<n;++i){
cin>>node[i].x>>node[i].y;
double v = atan2(node[i].y,node[i].x);
if(v<0){
v = v+2*PI;
}
node[i].val=v;
node[i].dis=sqrt(node[i].x*node[i].x+node[i].y*node[i].y);
}
sort(node,node+n,cmp1);
printf("case #%d:\n",cas++);
for(int i=0;i<n;++i){
printf("(%.4lf,%.4lf)\n",node[i].dis,node[i].val);
}
}
return 0;
}
B. 极坐标排序 - 编程思维与实践课程模拟练习 - ECNU Online Judge