python列表里的字典元素去重

去重:

from functools import reduce #导入排序模块

# 列表里的字典元素去重复
def list_dict_duplicate_removal(data_list):
    run_function = lambda x, y: x if y in x else x + [y]
    return reduce(run_function, [[], ] + data_list)


if __name__ == '__main__':
  data_list = [{"a": "123", "b": "321"}, {"a": "123", "b": "321"}, {"b": "321", "a": "123"}]
  
print list_dict_duplicate_removal(data_list)

输出结果:

[{'a': '123', 'b': '321'}]

python列表中元素去重的几种方式

class StringReverse(object):
    '''
    列表去重,并按照原来的顺序排序
    '''
 
    # 1.利用set方法和sort方法,原序
    def string_duplicate_1(self, s):
        new_s = list(set(s))  # set无序
        new_s.sort(key=s.index)
        return new_s
 
 
    # 2.用列表中的元素作为字典中的key生成一个新字典,然后获取字典的key,非原序
    def string_duplicate_2(self, s):
        a = {}
        # fromkeys(s,v)该方法的功能是生成一个字典,字典的key是 s中的值,s为可迭代对象,可以为str,tuple,list,set,dict,v为每一个key的值,默认为None
        return a.fromkeys(s).keys()
 
 
    # 3.利用defaultdict, 非原序
    def string_duplicate_3(self, s):
        # 按照之前的顺序
        from collections import defaultdict
        a = defaultdict()
        for x in s:
            a[x] = 0
        return a.keys()
 
    # 4.最简单的循环,添加入新的列表,如果新列表中没有相同元素,则加入。原序
    def string_duplicate_4(self, s):
        new_s = []
        for x in s:
            if x not in new_s:
                new_s.append(x)
        return new_s
 
 
    # 5.利用itertools的groupby方法。非原序
    def string_duplicate_5(self, s):
        from itertools import groupby
        s.sort()
        new_groupby = groupby(s)
        new_s = []
        for x,y in new_groupby:
            new_s.append(x)
        return new_s
 
    # 6.reduce方法。非原序
    def string_duplicate_6(self, s):
        return reduce(lambda x,y:x if y in x else x + [y], [[],] + s)
 
if __name__ == "__main__":
    stringReverse = StringReverse()
    s = [1,3,2,34,4,6,6,7,1,4,8,98]
    print "string_duplicate_1", stringReverse.string_duplicate_1(s)
    print "string_duplicate_2", stringReverse.string_duplicate_2(s)
    print "string_duplicate_3", stringReverse.string_duplicate_3(s)
    print "string_duplicate_4", stringReverse.string_duplicate_4(s)
    print "string_duplicate_5", stringReverse.string_duplicate_5(s)
    print "string_duplicate_6", stringReverse.string_duplicate_6(s) 

输出结果为:

string_duplicate_1 [1, 3, 2, 34, 4, 6, 7, 8, 98]

string_duplicate_2 [1, 2, 3, 4, 98, 6, 7, 8, 34]

string_duplicate_3 [1, 2, 3, 4, 98, 6, 7, 8, 34]

string_duplicate_4 [1, 3, 2, 34, 4, 6, 7, 8, 98]

string_duplicate_5 [1, 2, 3, 4, 6, 7, 8, 34, 98]

string_duplicate_6 [1, 2, 3, 4, 6, 7, 8, 34, 98]
————————————————

原文章:python列表里的字典元素去重 - zhangdingqu - 博客园
版权声明:本文为CSDN博主「SuperSpinach」的原创文章,遵循CC 4.0 BY-SA版权协议,转载请附上原文出处链接及本声明。
原文链接:https://blog.csdn.net/xzmlwwb/article/details/125735022



posted @ 2023-01-11 12:02  爱家家的卡卡  阅读(793)  评论(0编辑  收藏  举报