Simple one-hot state transition 3

合集 - Verilog学习(62)

1.Decade counter2024-04-102.Four-bit binary counter2024-04-103.Decade counter again2024-04-104.Slow decade counter2024-04-105.Counter 1-122024-04-106.Counter 10002024-04-107.4-digit decimal counter2024-04-108.12-hour clock2024-04-109.Hdlbits博文分布2024-04-1010.4-bit shift register2024-04-1111.Left/right rotator2024-04-1112.Left/right arithmetic shift by 1 or 82024-04-1113.5-bit LFSR2024-04-1114.3-bit LFSR2024-04-1115.32-bit LFSR2024-04-1116.Shift register2024-04-1117.Shift register(2)2024-04-1118.3-input LUT2024-04-1119.Rule 902024-04-1220.Rule 1102024-04-1221.Conway's Game of Life 16x162024-04-1222.Simple FSM1(asynchronous reset)2024-04-1423.Simple FSM1(synchronous reset)2024-04-1424.Simple FSM2(asynchronous reset)2024-04-1425.Simple FSM2(synchronous reset)2024-04-1426.Simple state transition 32024-04-14

27.Simple one-hot state transition 32024-04-14

28.Simple FSM 3（asynchronous reset）2024-04-1429.Simple FSM 3（synchronous reset）2024-04-1430.Design a Moore FSM2024-04-1431.Lemmings 12024-04-1432.Lemmings 22024-04-1433.Lemmings 32024-04-1534.Lemmings 42024-04-1535.One-hot FSM2024-04-1536.PS/2 packet parser2024-04-1537.PS/2 packet parser and datapath2024-04-1538.Serial receiver2024-04-1539.Serial receiver and datapath2024-04-1540.Serial receiver with parity checking2024-04-1541.Sequence recognition2024-04-1642.Q8:Design a Mealy FSM2024-04-1643.Q5a:Serial two's complementer(Moore FSM)2024-04-1644.Q5b:Serial two's complementer(Moore FSM)2024-04-1645.Q3a:FSM2024-04-1646.Q3b:FSM2024-04-1647.Q3c:FSM logic2024-04-1648.Q6b:FSM next-state logic2024-04-1649.Q6c:FSM next-state logic2024-04-1650.Q6:FSM2024-04-1651.Q2a：FSM2024-04-1652.Q2:One-hot FSM equations2024-04-1653.Q2a: FSM2024-04-1654.Q2b：Another FSM2024-04-1655.Counter with period 10002024-04-1656.4-bit shift register and down counter2024-04-1657.FSM:Sequence 1101 recognizer2024-04-1658.FSM:Enable shift register2024-04-1659.FSM:The complete FSM2024-04-1660.The complete timer2024-04-1661.FSM:One-hot logic equations2024-04-1662.UART2024-04-16

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The following is the state transition table for a Moore state machine with one input, one output, and four states. Use the following one-hot state encoding: A=4'b0001, B=4'b0010, C=4'b0100, D=4'b1000.

Derive state transition and output logic equations by inspection assuming a one-hot encoding. Implement only the state transition logic and output logic (the combinational logic portion) for this state machine. (The testbench will test with non-one hot inputs to make sure you're not trying to do something more complicated).

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module top_module(
    input in,
    input [3:0] state,
    output [3:0] next_state,
    output out); //

    parameter A=0, B=1, C=2, D=3;

    // State transition logic: Derive an equation for each state flip-flop.
    assign next_state[A] = ((state[A])&&(!in))||((state[C])&&(!in));
    assign next_state[B] = ((state[A])&&(in))||((state[B])&&(in))||((state[D])&&(in));
    assign next_state[C] = ((state[B])&&(!in))||((state[D])&&(!in));
    assign next_state[D] = ((state[C])&&(in));

    // Output logic: 
    assign out = (state[D])?1:0;

endmodule

这个题目中表示state是否是我们需要的状态的写法可以学学next_state[A]