4-digit decimal counter
1.Decade counter2.Four-bit binary counter3.Decade counter again4.Slow decade counter5.Counter 1-126.Counter 1000
7.4-digit decimal counter
8.12-hour clock9.Hdlbits博文分布10.4-bit shift register11.Left/right rotator12.Left/right arithmetic shift by 1 or 813.5-bit LFSR14.3-bit LFSR15.32-bit LFSR16.Shift register17.Shift register(2)18.3-input LUT19.Rule 9020.Rule 11021.Conway's Game of Life 16x1622.Simple FSM1(asynchronous reset)23.Simple FSM1(synchronous reset)24.Simple FSM2(asynchronous reset)25.Simple FSM2(synchronous reset)26.Simple state transition 327.Simple one-hot state transition 328.Simple FSM 3(asynchronous reset)29.Simple FSM 3(synchronous reset)30.Design a Moore FSM31.Lemmings 132.Lemmings 233.Lemmings 334.Lemmings 435.One-hot FSM36.PS/2 packet parser37.PS/2 packet parser and datapath38.Serial receiver39.Serial receiver and datapath40.Serial receiver with parity checking41.Sequence recognition42.Q8:Design a Mealy FSM43.Q5a:Serial two's complementer(Moore FSM)44.Q5b:Serial two's complementer(Moore FSM)45.Q3a:FSM46.Q3b:FSM47.Q3c:FSM logic48.Q6b:FSM next-state logic49.Q6c:FSM next-state logic50.Q6:FSM51.Q2a:FSM52.Q2:One-hot FSM equations53.Q2a: FSM54.Q2b:Another FSM55.Counter with period 100056.4-bit shift register and down counter57.FSM:Sequence 1101 recognizer58.FSM:Enable shift register59.FSM:The complete FSM60.The complete timer61.FSM:One-hot logic equations62.UARTBuild a 4-digit BCD (binary-coded decimal) counter. Each decimal digit is encoded using 4 bits: q[3:0] is the ones digit, q[7:4] is the tens digit, etc. For digits [3:1], also output an enable signal indicating when each of the upper three digits should be incremented.
module top_module (
input clk,
input reset, // Synchronous active-high reset
output [3:1] ena,
output [15:0] q);
reg [3:0]ones;
reg [3:0]tens;
reg [3:0]hundreds;
reg [3:0]thousands;
always@(posedge clk)begin
if(reset)begin
ones<=4'b0;
end
else begin
if(ones==4'd9)begin
ones<=4'b0;
end
else begin
ones<=ones+4'd1;
end
end
end
always@(posedge clk)begin
if(reset)begin
tens<=4'b0;
end
else begin
if(ones==4'd9&&tens==4'd9)begin
tens<=4'b0;
end
else if(ones==4'd9)begin
tens<=tens+4'd1;
end
end
end
always@(posedge clk)begin
if(reset)begin
hundreds<=4'b0;
end
else begin
if(ones==4'd9&&tens==4'd9&&hundreds==4'd9)begin
hundreds<=4'b0;
end
else if(ones==4'd9&&tens==4'd9)begin
hundreds<=hundreds+4'd1;
end
end
end
always@(posedge clk)begin
if(reset)begin
thousands<=4'b0;
end
else begin
if(ones==4'd9&&tens==4'd9&&hundreds==4'd9&&thousands==4'd9)begin
thousands<=4'b0;
end
else if(ones==4'd9&&tens==4'd9&&hundreds==4'd9)begin
thousands<=thousands+4'd1;
end
end
end //上面的四个模块分别是对个十百千位进行逐位递增判断
assign q={thousands,hundreds,tens,ones}; //对最终输出开始赋值
assign ena[1] = (ones == 4'd9) ? 1'b1 : 1'b0;
assign ena[2] = ((ones == 4'd9) && (tens == 4'd9)) ? 1'b1 : 1'b0;
assign ena[3] = ((ones == 4'd9) && (tens == 4'd9) && (hundreds == 4'd9)) ? 1'b1 : 1'b0; //与上一题一致
endmodule
合集:
Verilog学习
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