2039 津津的储蓄计划

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 1e3+10,inf = 0x3f3f3f3f;

int main()
{
    int money = 0,c = 0,s;
    for(int i = 1; i <= 12; i++)
    {
        int x; cin >> x;
        money += 300;
        money -= x;
        s = money / 100;
        c += s * 100;
        money -= s * 100;
        if(money < 0)
        {
            cout << -i;return 0;
        }
    }
    cout << c * 1.2 + money;
    return 0;
}

 

posted @ 2024-06-28 14:51  CRt0729  阅读(8)  评论(0编辑  收藏  举报