658. Find K Closest Elements

Given a sorted array, two integers k and x, find the k closest elements to x in the array. The result should also be sorted in ascending order. If there is a tie, the smaller elements are always preferred.

Example 1:

Input: [1,2,3,4,5], k=4, x=3
Output: [1,2,3,4]

 

Example 2:

Input: [1,2,3,4,5], k=4, x=-1
Output: [1,2,3,4]

 

Note:

1. The value k is positive and will always be smaller than the length of the sorted array.
2. Length of the given array is positive and will not exceed 104
3. Absolute value of elements in the array and x will not exceed 104

class Solution {
public:
    vector<int> findClosestElements(vector<int>& arr, int k, int x) {
         int n = arr.size();
         if(n<k) return arr;
         int idx = binary_search(arr,x);
         cout << idx << endl;
         int left = max(0,idx-k);
         int right = min(idx+k,n-1);
         vector<int> res;
         while(left<right)
         {
             if(abs(arr[left]-x)<=abs(arr[right]-x))
                 right--;
             else
                 left++;
             if((right-left+1)==k) break;
         }
         for(int i = left;i<=right;i++)
             res.push_back(arr[i]);
         return res;
    }
private:
    int binary_search(vector<int>&arr,int x)
    {
        int left = 0,right=arr.size()-1;
        while(left<right)
        {
            int mid = (left+right)/2;
            if(arr[mid]==x) return mid;
            else if(arr[mid]>x) right = mid-1;
            else left = mid+1;
        }
        return left;
    }
};