Web.py Cookbook 简体中文版 - 如何流传输大文件
2012-11-23 11:07 justjavac 阅读(281) 评论(0) 编辑 收藏 举报问题
如何流传输大文件?
解法
要流传输大文件,需要添加传输译码(Transfer-Encoding)区块头,这样才能一边下载一边显示。否则,浏览器将缓冲所有数据直到下载完毕才显示。
如果这样写:直接修改基础字符串(例中就是j),然后用Yield返回--是没有效果的。如果要使用Yield,就要向对所有内容使用yield。因为这个函式此时是一个产生器。(注:请处请详看Yield文档,在此不做过多论述。)
例子
# Simple streaming server demonstration
# Uses time.sleep to emulate a large file read
import web
import time
urls = (
"/", "count_holder",
"/(.*)", "count_down",
)
app = web.application(urls, globals())
class count_down:
def GET(self,count):
# These headers make it work in browsers
web.header('Content-type','text/html')
web.header('Transfer-Encoding','chunked')
yield '<h2>Prepare for Launch!</h2>'
j = '<li>Liftoff in %s...</li>'
yield '<ul>'
count = int(count)
for i in range(count,0,-1):
out = j % i
time.sleep(1)
yield out
yield '</ul>'
time.sleep(1)
yield '<h1>Lift off</h1>'
class count_holder:
def GET(self):
web.header('Content-type','text/html')
web.header('Transfer-Encoding','chunked')
boxes = 4
delay = 3
countdown = 10
for i in range(boxes):
output = '<iframe src="/%d" width="200" height="500"></iframe>' % (countdown - i)
yield output
time.sleep(delay)
if __name__ == "__main__":
app.run()