amazon笔试题
下面是来自于亚马逊的编程笔试题,感兴趣的同学可以先自己想想解题思路:
Please implement a simple logic rule, the input is a set of logic formula, the format is like a1,a2,a3,…,an->b, which means a1,a2,a3,…an can deduce b. It meets the following rules:
1. If A->B B->C then A->C
2. If A,B->C D->A then D,B->C
3. If A,B->C then B,A->C
The input contains two lines:
1. The first line contains n (100>n>0) base formulas, separated by spaces
2. The second line contains m (100>m>0) formulas that need to check true or false according to above n formulas, separated by spaces
The output should be m lines, if the i-th formula in the second line can be deduced by the n base formulas, the i-th line should be "true", otherwise, "false".
Each element is a case sensitive alphabet, to simplify the parsing work, “->” is replaced by ">", there might be more than 1 character on the left side and only one on the right side, the following is an example: A,B,C>D
Sample Input and Output
Input
A>B B>C
A>C
Output
true
Input
A,B>C D,E>A E>B
E,D>C F,E>C
Output
true
false
Input
A>B A,B>C
A>C
Output
true
Please complement the matchRule method in Solution class:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Solution {
public static void main(String[] args) throws IOException {
InputStreamReader isr = new InputStreamReader(System.in);
BufferedReader br = new BufferedReader(isr);
String baseRules = br.readLine();
String checkingRules = br.readLine();
matchRule(baseRules, checkingRules);
br.close();
isr.close();
}
private static void matchRule(String baseRules, String checkingRules) {
}
}
1 import java.io.BufferedReader; 2 import java.io.IOException; 3 import java.io.InputStreamReader; 4 import java.util.HashMap; 5 import java.util.Vector; 6 7 8 public class Solution { 9 10 11 private static HashMap<String, node> nodeAlreadyHave = new HashMap<String, node>(); 12 public static void main(String[] args) throws IOException { 13 InputStreamReader isr = new InputStreamReader(System.in); 14 BufferedReader br = new BufferedReader(isr); 15 16 // String baseRules = "A>B A,B>C"; 17 // String checkingRules = "A>C"; 18 String baseRules = br.readLine(); 19 String checkingRules = br.readLine(); 20 21 matchRule(baseRules, checkingRules); 22 23 br.close(); 24 isr.close(); 25 } 26 static class node{ 27 String identified; 28 Vector<node> nextnodes = null; 29 int count; 30 31 node(String name) 32 { 33 identified = name; 34 count = 0; 35 nextnodes = new Vector<node>(); 36 } 37 38 boolean after(node t) 39 { 40 if(identified.equals(t.identified)) 41 return true; 42 for(int i = 0;i < nextnodes.size(); i++) 43 { 44 if(nextnodes.get(i).after(t)) 45 return true; 46 } 47 return false; 48 } 49 } 50 private static void matchRule(String baseRules, String checkingRules) { 51 System.out.println("test"); 52 String[] baseRulesArray = baseRules.split(" "); 53 for(int i=0 ;i < baseRulesArray.length; i++) 54 { 55 System.out.println(baseRulesArray[i]); 56 57 } 58 59 parseRule(baseRulesArray); 60 String[] checkingRulesArray = checkingRules.split(" "); 61 for(int i=0 ;i < checkingRulesArray.length; i++) 62 { 63 System.out.println(checkingRulesArray[i]); 64 checkRules(checkingRulesArray[i]); 65 } 66 67 68 69 } 70 71 private static void parseRule(String[] rules) 72 { 73 for(int i = 0 ; i < rules.length;i++) 74 { 75 String[] token = rules[i].split("[, >]"); 76 node t; 77 if(!nodeAlreadyHave.containsKey(token[token.length-1])) 78 { 79 t = new node(token[token.length-1]); 80 nodeAlreadyHave.put(token[token.length-1], t); 81 }else { 82 t = nodeAlreadyHave.get(token[token.length-1]); 83 } 84 for(int j=0 ;j< token.length-1; j++) 85 { 86 node s; 87 if(!nodeAlreadyHave.containsKey(token[j])) 88 { 89 s = new node(token[j]); 90 nodeAlreadyHave.put(token[j], s); 91 }else{ 92 s = nodeAlreadyHave.get(token[j]); 93 } 94 s.nextnodes.add(t); 95 96 //System.out.println("token "+token[j]); 97 } 98 } 99 100 } 101 102 private static void checkRules(String checkRule) 103 { 104 String[] token = checkRule.split("[, >]"); 105 node t; 106 if(!nodeAlreadyHave.containsKey(token[token.length-1])) 107 { 108 System.out.println("false"); 109 return ; 110 }else { 111 t = nodeAlreadyHave.get(token[token.length-1]); 112 } 113 for(int j=0 ;j< token.length-1; j++) 114 { 115 node s; 116 if(!nodeAlreadyHave.containsKey(token[j])) 117 { 118 System.out.println("false"); 119 return ; 120 }else{ 121 s = nodeAlreadyHave.get(token[j]); 122 } 123 if(s.after(t)) 124 { 125 System.out.println("true"); 126 return; 127 } 128 129 130 } 131 System.out.println("false"); 132 } 133 134 135 136 137 }