如何配置Unity的Behaviors for Interception

继续前一篇实现的NotifyPropertyChangedBehavior,如何在配置文件中添加:

<?xml version=”1.0″ encoding=”utf-8″ ?>
<configuration>
  <configSections>
    <section name=”unity” type=”Microsoft.Practices.Unity.Configuration.UnityConfigurationSection, Microsoft.Practices.Unity.Configuration”/>
  </configSections>

  <unity xmlns=”http://schemas.microsoft.com/practices/2010/unity”>
    <sectionExtension type=”Microsoft.Practices.Unity.InterceptionExtension.Configuration.InterceptionConfigurationExtension, Microsoft.Practices.Unity.Interception.Configuration” />

    <assembly name=”mscorlib, 2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089″ />
    <assembly name=”UnityTest5″ />

    <namespace name=”System.ComponentModel” />
    <namespace name=”UnityTest5″ />

    <container>
      <extension type=”Interception” />

      <register type=”MainViewModel”>
        <interceptor type=”VirtualMethodInterceptor” />
        <addInterface type=”INotifyPropertyChanged” />
        <interceptionBehavior type=”NotifyPropertyChangedBehavior” />
      </register>
    </container>
  </unity>
</configuration>

默认Unity的配置无法识别interceptor,需要在unity配置节中添加一个sectionExtension,由InterceptionConfigurationExtension处理(Microsoft.Practices.Unity.Interception.Configuration.dll)。

代码中使用:

1 IUnityContainer unityContainer = new UnityContainer();
2 
3 unityContainer.LoadConfiguration();
4 
5 MainViewModel viewModel = unityContainer.Resolve<MainViewModel>();
6 
7 ((INotifyPropertyChanged)viewModel).PropertyChanged += new PropertyChangedEventHandler((sender, e) => Console.WriteLine(e.PropertyName));
8 
9 viewModel.Name = “hello, world”;
posted @ 2012-08-10 11:38  junchu25  阅读(439)  评论(0编辑  收藏  举报