selenium 对滑动验证框的处理

在登录的时候,有的系统会采用滑动验证的方式,今天贴下这里的代码自己学习。

使用selenium  行为事件方法ActionChains 方法,把我么要滑动的动作放进列表,然后交给selenium执行,具体的算法是其他大佬搞出来的

经过本人验证,可以识别

http://guapier.net/2019/04/12/aliyun/

import time
import random
from selenium import webdriver
from selenium.webdriver import ActionChains

url = "xxxxx"
user = "xxxxxx"
pas = "123123"

def get_track(distance):      # distance为传入的总距离
    # 移动轨迹
    track = []
    # 当前位移
    current = 0
    # 减速阈值
    mid = distance*4/5
    # 计算间隔
    t = 0.2
    # 初速度
    v = 1

    while current < distance:
        if current < mid:
            # 加速度为2
            a = random.uniform(0, 2)
        else:
            # 加速度为-2
            a = random.uniform(-1, -2)
        v0 = v
        # 当前速度
        v = v0 + a*t
        # 移动距离
        move = v0*t+1/2*a*t*t
        # 当前位移
        current += move
        # 加入轨迹
        track.append(round(move))
    return track
def move_to_gap(driver, slider,tracks):     # slider是要移动的滑块,tracks是要传入的移动轨迹
    ActionChains(driver).click_and_hold(slider).perform()
    for x in tracks:
        ActionChains(driver).move_by_offset(xoffset=x, yoffset=0).perform()
    time.sleep(0.5)
    ActionChains(driver).release().perform()

def login():
    driver = webdriver.Chrome()
    driver.get(url)
    time.sleep(5)
    driver.find_element_by_xpath('xxxxx').send_keys(user)
    driver.find_element_by_xpath('xxxxx').send_keys(pas)
    huakuai = driver.find_element_by_xpath('xxxxx')
    time.sleep(5)
    move_to_gap(driver, huakuai, get_track(340))
    time.sleep(5)
    driver.find_element_by_xpath('xxxxxxx').click()
    time.sleep(60)

if __name__ == "__main__":
    login()

  

posted @ 2020-09-04 15:34  绝世老中医  阅读(595)  评论(0编辑  收藏  举报