IP Address 分类: POJ 2015-06-12 19:34 12人阅读 评论(0) 收藏
IP Address
Time Limit: 1000MS | Memory Limit: 30000K | |
Total Submissions: 19125 | Accepted: 11053 |
Description
Suppose you are reading byte streams from any device, representing IP addresses. Your task is to convert a 32 characters long sequence of '1s' and '0s' (bits) to a dotted decimal format. A dotted decimal format for an IP address
is form by grouping 8 bits at a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the
first 8 positions of the binary systems are:
27 26 25 24 23 22 21 20 128 64 32 16 8 4 2 1
Input
The input will have a number N (1<=N<=9) in its first line representing the number of streams to convert. N lines will follow.
Output
The output must have N lines with a doted decimal IP address. A dotted decimal IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation.
Sample Input
4 00000000000000000000000000000000 00000011100000001111111111111111 11001011100001001110010110000000 01010000000100000000000000000001
Sample Output
0.0.0.0 3.128.255.255 203.132.229.128 80.16.0.1
二进制转化
#include <cstdio> #include <string.h> #include <cmath> #include <iostream> #include <algorithm> #define WW freopen("output.txt","w",stdout) using namespace std; int main() { char s[100]; int T; scanf("%d",&T); while(T--) { scanf("%s",s); int len=strlen(s); int a[5]; int sum=0,ans=1; for(int j=1,i=len-1;i>=0;i--,j++) { if(j%8) { sum=(s[i]-'0')*ans+sum; ans*=2; } else { sum=(s[i]-'0')*ans+sum; ans=1; a[j/8]=sum; sum=0; } } printf("%d.%d.%d.%d\n",a[4],a[3],a[2],a[1]); } return 0; }
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