Case of the Zeros and Ones 分类: CF 2015-07-24 11:05 15人阅读 评论(0) 收藏

A. Case of the Zeros and Ones
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.

Once he thought about a string of length n consisting of zeroes and ones. Consider the following operation: we choose any twoadjacent positions in the string, and if one them contains 0, and the other contains 1, then we are allowed to remove these two digits from the string, obtaining a string of lengthn - 2 as a result.

Now Andreid thinks about what is the minimum length of the string that can remain after applying the described operation several times (possibly, zero)? Help him to calculate this number.

Input

First line of the input contains a single integer n (1 ≤ n ≤ 2·105), the length of the string that Andreid has.

The second line contains the string of length n consisting only from zeros and ones.

Output

Output the minimum length of the string that may remain after applying the described operations several times.

Sample test(s)
Input
4
1100
Output
0
Input
5
01010
Output
1
Input
8
11101111
Output
6
CF的一道水题
#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstdlib>
#include <cstring>
#include <stack>
#include <algorithm>

using namespace std;

const int MAX = 200200;

char str[MAX];

int main()
{
    int n;
    scanf("%d",&n);
    scanf("%s",str);
    int a=0,b=0;
    for(int i=0;i<n;i++)
    {
        if(str[i]=='0')
        {
            a++;
        }
        else
        {
            b++;
        }
    }
    int sum=abs(a-b);
    printf("%d\n",sum);
    return 0;

}


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posted @ 2015-07-24 11:05  一骑绝尘去  阅读(120)  评论(0编辑  收藏  举报