摘要: 后序遍历就行。//寻找二叉树两个结点的最低共同父节点TreeNode *FindFirstCommonParentNode(TreeNode *pRoot, TreeNode *pNodeOne, TreeNode *pNodeTwo){ if (NULL == pRoot) { ... 阅读全文
posted @ 2014-12-01 21:59 juandx 阅读(227) 评论(0) 推荐(0) 编辑