结构体的赋值和初始化与取出结构体变量中的成员

 1 /*结构体的赋值和初始化*/
 2 
 3 # include <stdio.h>
 4 
 5 struct Student 
 6 {
 7     int age;
 8     float score;
 9     char sex;
10 };
11 
12 int main(void)
13 {
14     struct Student st = { 80, 66.6, 'F'};//定义同时就赋值
15     struct Student st2;//下一行不能写一句类似于st2 = { 10, 88, 'M'};的语句，除非定义时就赋值。
16     st2.age = 10;
17     st2.score = 88;
18     st2.sex = 'M';
19 
20     printf("%d , %f, %c\n", st.age, st.score, st.sex);
21     printf("%d , %f, %c\n", st2.age, st2.score, st2.sex);
22 
23     return 0;
24 }
25 /*
26 在Vc++6.0中显示的结果是：
27 =========================================
28 80 , 66.599998, F
29 10 , 88.000000, M
30 =========================================
31 */

 

  1 /*

 2 如何取出结构体变量中的每一个成员
 3 */
 4 # include <stdio.h>
 5 
 6 struct Student 
 7 {
 8     int age;
 9     float score;
10     char sex;
11 };
12 
13 int main(void)
14 {
15     struct Student st = { 80, 66.6F, 'F'};
16     printf("age = %d\n",st.age);
17 
18 
19     struct Student * pst = &st;//&st不能改成st
20     pst->age = 88;  //第二种方式。。。pst->age在计算机内部，会被转化成(*pst).age 这是一种硬性规定
21                     //所以pst->age等价于(*pst).age ，也等价于st.age
22     printf("age = %d\n",st.age);
23 
24 
25     st.age = 10;  //第一种方式
26     printf("age = %d, score = %f\n",st.age, pst ->score);//st.age可写成pst ->age, pst ->score也可写成st.score.
27 
28     return 0;
29 }
30 /*
31 在Vc++6.0中显示的结果是：
32 ==============================================================
33 age = 80
34 age = 88
35 age = 10, score = 66.599998
36 ==============================================================
37 */