codeforces 1264 B 贪心xg

 

题意：给了4个数0，1，2，3。的数量a，b，c，d。要组成一个排列abs(ai+1-ai)等于1。组成不了则输出no，否则输出任意排列顺序。

思路：ifelse暴力肯定是能做的。最先是想查询从出现最多次数的数字贪心，如果前面一个数的数量不等于0，则游动下标pos--，否则pos++；后来发现这样有些样例过不了。

　　因为就4个数字，索性直接四个数字全都当首字母暴力搞一搞，然后判断队列中有多少个字符瞎搞即可。

　　

#include <iostream>
#include <cmath>
#include <cstdio>
#include <cstring>
#include <string>
#include <map>
#include <iomanip>
#include <algorithm>
#include <queue>
#include <stack>
#include <set>
#include <vector> 
// #include <bits/stdc++.h>
#define fastio ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define sp ' '
#define endl '\n'
#define inf  0x3f3f3f3f;
#define FOR(i,a,b) for( int i = a;i <= b;++i)
#define bug cout<<"--------------"<<endl
#define P pair<int, int>
#define fi first
#define se second
#define pb(x) push_back(x)
#define ppb() pop_back()
#define mp(a,b) make_pair(a,b)
#define ms(v,x) memset(v,x,sizeof(v))
#define rep(i,a,b) for(int i=a;i<=b;i++)
#define repd(i,a,b) for(int i=a;i>=b;i--)
#define sca3(a,b,c) scanf("%d %d %d",&(a),&(b),&(c))
#define sca2(a,b) scanf("%d %d",&(a),&(b))
#define sca(a) scanf("%d",&(a));
#define sca3ll(a,b,c) scanf("%lld %lld %lld",&(a),&(b),&(c))
#define sca2ll(a,b) scanf("%lld %lld",&(a),&(b))
#define scall(a) scanf("%lld",&(a));


using namespace std;
typedef long long ll;
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
ll lcm(ll a,ll b){return a/gcd(a,b)*b;}
ll powmod(ll a, ll b, ll mod){ll sum = 1;while (b) {if (b & 1) {sum = (sum * a) % mod;b--;}b /= 2;a = a * a % mod;}return sum;}

const double Pi = acos(-1.0);
const double epsilon = Pi/180.0;
const int maxn = 2e5+10;
//int a[5];
map<int,int>a;
int b[maxn];
void hhh()
{
    rep(i,0,3){
    a[i] = b[i];
    //sum += a[i];
    }
}
int main()
{
    //freopen("input.txt", "r", stdin);
    //ll a,b,c,d;
    int sum  = 0;
    rep(i,-1,4){
        a[i] = 0;
    }
    rep(i,0,3){
        cin>>a[i];
        b[i] = a[i];
        sum += a[i];
    }
    queue<int>que;
    int flag = 0;
    rep(i,0,3){
        hhh();
        if(a[i] == 0) continue;
        int pos = i;
        string s = "0123";
        //que.clear();
        while(que.size()){
            que.pop();
        }
        while(1){
            a[pos]--;
            que.push(s[pos]);

            if(a[pos-1]){
                pos--;
            }
            else if(a[pos+1]){
                pos++;
            }
            else {
                break;
            }
        }        
        if(que.size() == sum) {
            flag = 1;
            break;
        }
    }
    if(flag == 0){
        cout<<"NO"<<endl;
    }
    else {
        cout<<"YES"<<endl;
        while(que.size()){
            char tmp = que.front();
            que.pop();
            cout<<tmp<<sp;
        }        
    }
}