排序算法

 

计算时间的迭代器

import time
def cal_time(func):
    def wrapper(*args, **kwargs):
        t1 = time.time()
        result = func(*args, **kwargs)
        t2 = time.time()
        print("%s running time: %s secs." % (func.__name__, t2 - t1))
        return result
    return wrapper

 

冒泡排序

#coding=utf-8
from cal_time import cal_time

@cal_time
def bubble_sort(li):
    for i in range(0,len(li)-1):
        exchange=False
        for j in range(0,len(li)-i-1):
            if li[j] > li[j+1]:
                li[j],li[j+1]=li[j+1],li[j]
                exchange=True
        if not exchange:
            break


@cal_time
def bubble_sort2(li):
    #i表示第i趟,延续区有i个数
    for i in range(len(li)-1,0,-1):
        for j in range(len(li)-1-i,0,-1):
            if li[j-1] < li[j]:
                li[j - 1], li[j]=li[j],li[j-1]

import random
li =list(range(10000))
random.shuffle(li)
# bubble_sort2(li)
bubble_sort(li)
print(li)
View Code

选择排序

from cal_time import cal_time

@cal_time
def select_sort(li):
    #第i趟,有序列li[0:i],无序列li[i,n]
    for i in range(len(li)-1):
        min_loc=i
        for j in range(i+1,len(li)):
            if li[min_loc]>li[j]:
                min_loc=j
        li[i],li[min_loc]=li[min_loc],li[i]

import random
li=list(range(10000))
random.shuffle(li)
select_sort(li)
print(li)
View Code

插入排序

def insert_sort(li):
    for i in range(1,len(li)):
        #i表示趟数,也表示摸到牌的下标
        j=i-1
        tmp=li[i]
        while j>=0 and li[j]>tmp:
            li[j+1]=li[j]
            j-=1
        li[j+1]=tmp

import random
li =list(range(10000))
random.shuffle(li)
insert_sort(li)
print(li)
View Code

快速排序

from cal_time import cal_time

def partition(li,left,right):
    i=random.randint(left,right)
    li[i],li[left]=li[left],li[i]
    tmp=li[left]
    while left<right:
        #从右边找到比tmp小的数
        while left<right and li[right]>=tmp:
            right-=1
        li[left]=li[right]
        #从左边找比temp大的数
        while left<right and li[left]<=tmp:
            left+=1
        li[right]=li[left]
    li[left]=tmp
    return left


def _quick_sort(li,left,right):
    if left<right:
        mid=partition(li,left,right)
        _quick_sort(li,left,mid-1)
        _quick_sort(li,mid+1,right)

@cal_time
def quick_sort(li):
    return _quick_sort(li,0,len(li)-1)

import random
li=list(range(10000))
random.shuffle(li)
quick_sort(li)
print(li)
View Code

堆排序

from cal_time import cal_time

def sift(data, low, high):
    i = low
    j = 2 * i + 1
    tmp = data[i]
    while j <= high:    #孩子在堆里
        if j + 1 <= high and data[j] < data[j+1]:   #如果有右孩子且比左孩子大
            j += 1  #j指向右孩子
        if data[j] > tmp:   #孩子比最高领导大
            data[i] = data[j]   #孩子填到父亲的空位上
            i = j               #孩子成为新父亲
            j = 2 * i +1        #新孩子
        else:
            break
    data[i] = tmp           #最高领导放到父亲位置


@cal_time
def heap_sort(data):
    n = len(data)
    for i in range(n // 2 - 1, -1, -1):
        sift(data, i, n - 1)
    #堆建好了
    #挨个换数
    for i in range(n-1, -1, -1):
        data[0], data[i] = data[i], data[0]
        sift(data, 0, i - 1)

li=list(range(10000))
import random
random.shuffle(li)
heap_sort(li)
print(li)
View Code

归并排序

def merge(li, low, mid, high):
    i = low
    j = mid + 1
    ltmp = []
    while i <= mid and j <= high:
        if li[i] <= li[j]:
            ltmp.append(li[i])
            i += 1
        else:
            ltmp.append(li[j])
            j += 1
    while i <= mid:
        ltmp.append(li[i])
        i += 1
    while j <= high:
        ltmp.append(li[j])
        j += 1
    li[low:high + 1] = ltmp



def mergesort(li, low, high):
    if low < high:
        mid = (low + high) // 2
        mergesort(li, low, mid)
        mergesort(li, mid + 1, high)
        merge(li, low, mid, high)

li=[2,5,7,8,9,1,3,4,6]
mergesort(li,0,len(li)-1)
print(li)
View Code

直接插入排序最好时间复杂度为O(n)

 

 

 

 

 

posted @ 2019-01-26 20:48  JRB  阅读(125)  评论(0编辑  收藏  举报