如何合理地估算线程池大小?

感谢网友【蒋小强】投稿。

如何合理地估算线程池大小?

这个问题虽然看起来很小,却并不那么容易回答。大家如果有更好的方法欢迎赐教,先来一个天真的估算方法:假设要求一个系统的TPS(Transaction Per Second或者Task Per Second)至少为20,然后假设每个Transaction由一个线程完成,继续假设平均每个线程处理一个Transaction的时间为4s。那么问题转化为:

如何设计线程池大小,使得可以在1s内处理完20个Transaction?

计算过程很简单,每个线程的处理能力为0.25TPS,那么要达到20TPS,显然需要20/0.25=80个线程。

很显然这个估算方法很天真,因为它没有考虑到CPU数目。一般服务器的CPU核数为16或者32,如果有80个线程,那么肯定会带来太多不必要的线程上下文切换开销。

再来第二种简单的但不知是否可行的方法(N为CPU总核数):

  • 如果是CPU密集型应用,则线程池大小设置为N+1
  • 如果是IO密集型应用,则线程池大小设置为2N+1

如果一台服务器上只部署这一个应用并且只有这一个线程池,那么这种估算或许合理,具体还需自行测试验证。

接下来在这个文档:服务器性能IO优化 中发现一个估算公式:

最佳线程数目 = ((线程等待时间+线程CPU时间)/线程CPU时间 )* CPU数目

比如平均每个线程CPU运行时间为0.5s,而线程等待时间(非CPU运行时间,比如IO)为1.5s,CPU核心数为8,那么根据上面这个公式估算得到:((0.5+1.5)/0.5)*8=32。这个公式进一步转化为:

最佳线程数目 = (线程等待时间与线程CPU时间之比 + 1)* CPU数目

可以得出一个结论:

线程等待时间所占比例越高,需要越多线程。线程CPU时间所占比例越高,需要越少线程。

上一种估算方法也和这个结论相合。

一个系统最快的部分是CPU,所以决定一个系统吞吐量上限的是CPU。增强CPU处理能力,可以提高系统吞吐量上限。但根据短板效应,真实的系统吞吐量并不能单纯根据CPU来计算。那要提高系统吞吐量,就需要从“系统短板”(比如网络延迟、IO)着手:

  • 尽量提高短板操作的并行化比率,比如多线程下载技术
  • 增强短板能力,比如用NIO替代IO

第一条可以联系到Amdahl定律,这条定律定义了串行系统并行化后的加速比计算公式:

加速比=优化前系统耗时 / 优化后系统耗时

加速比越大,表明系统并行化的优化效果越好。Addahl定律还给出了系统并行度、CPU数目和加速比的关系,加速比为Speedup,系统串行化比率(指串行执行代码所占比率)为F,CPU数目为N:

Speedup <= 1 / (F + (1-F)/N)

当N足够大时,串行化比率F越小,加速比Speedup越大。

写到这里,我突然冒出一个问题。

是否使用线程池就一定比使用单线程高效呢?

答案是否定的,比如Redis就是单线程的,但它却非常高效,基本操作都能达到十万量级/s。从线程这个角度来看,部分原因在于:

  • 多线程带来线程上下文切换开销,单线程就没有这种开销

当然“Redis很快”更本质的原因在于:Redis基本都是内存操作,这种情况下单线程可以很高效地利用CPU。而多线程适用场景一般是:存在相当比例的IO和网络操作。

所以即使有上面的简单估算方法,也许看似合理,但实际上也未必合理,都需要结合系统真实情况(比如是IO密集型或者是CPU密集型或者是纯内存操作)和硬件环境(CPU、内存、硬盘读写速度、网络状况等)来不断尝试达到一个符合实际的合理估算值。

最后来一个“Dark Magic”估算方法(因为我暂时还没有搞懂它的原理),使用下面的类:

package pool_size_calculate;

import java.math.BigDecimal;
import java.math.RoundingMode;
import java.util.Timer;
import java.util.TimerTask;
import java.util.concurrent.BlockingQueue;

/**

  • A class that calculates the optimal thread pool boundaries. It takes the
  • desired target utilization and the desired work queue memory consumption as
  • input and retuns thread count and work queue capacity.
  • @author Niklas Schlimm

*/
public abstract class PoolSizeCalculator {

/**
 * The sample queue size to calculate the size of a single {@link Runnable}
 * element.
 */
private final int SAMPLE_QUEUE_SIZE = 1000;

/**
 * Accuracy of test run. It must finish within 20ms of the testTime
 * otherwise we retry the test. This could be configurable.
 */
private final int EPSYLON = 20;

/**
 * Control variable for the CPU time investigation.
 */
private volatile boolean expired;

/**
 * Time (millis) of the test run in the CPU time calculation.
 */
private final long testtime = 3000;

/**
 * Calculates the boundaries of a thread pool for a given {@link Runnable}.
 *
 * @param targetUtilization
 *            the desired utilization of the CPUs (0 &lt;= targetUtilization &lt;= 	 *            1) 	 * @param targetQueueSizeBytes 	 *            the desired maximum work queue size of the thread pool (bytes) 	 */ 	protected void calculateBoundaries(BigDecimal targetUtilization, 			BigDecimal targetQueueSizeBytes) { 		calculateOptimalCapacity(targetQueueSizeBytes); 		Runnable task = creatTask(); 		start(task); 		start(task); // warm up phase 		long cputime = getCurrentThreadCPUTime(); 		start(task); // test intervall 		cputime = getCurrentThreadCPUTime() - cputime; 		long waittime = (testtime * 1000000) - cputime; 		calculateOptimalThreadCount(cputime, waittime, targetUtilization); 	} 	private void calculateOptimalCapacity(BigDecimal targetQueueSizeBytes) { 		long mem = calculateMemoryUsage(); 		BigDecimal queueCapacity = targetQueueSizeBytes.divide(new BigDecimal( 				mem), RoundingMode.HALF_UP); 		System.out.println("Target queue memory usage (bytes): " 				+ targetQueueSizeBytes); 		System.out.println("createTask() produced " 				+ creatTask().getClass().getName() + " which took " + mem 				+ " bytes in a queue"); 		System.out.println("Formula: " + targetQueueSizeBytes + " / " + mem); 		System.out.println("* Recommended queue capacity (bytes): " 				+ queueCapacity); 	} 	/** 	 * Brian Goetz' optimal thread count formula, see 'Java Concurrency in 	 * Practice' (chapter 8.2) 	 *  	 * @param cpu 	 *            cpu time consumed by considered task 	 * @param wait 	 *            wait time of considered task 	 * @param targetUtilization 	 *            target utilization of the system 	 */ 	private void calculateOptimalThreadCount(long cpu, long wait, 			BigDecimal targetUtilization) { 		BigDecimal waitTime = new BigDecimal(wait); 		BigDecimal computeTime = new BigDecimal(cpu); 		BigDecimal numberOfCPU = new BigDecimal(Runtime.getRuntime() 				.availableProcessors()); 		BigDecimal optimalthreadcount = numberOfCPU.multiply(targetUtilization) 				.multiply( 						new BigDecimal(1).add(waitTime.divide(computeTime, 								RoundingMode.HALF_UP))); 		System.out.println("Number of CPU: " + numberOfCPU); 		System.out.println("Target utilization: " + targetUtilization); 		System.out.println("Elapsed time (nanos): " + (testtime * 1000000)); 		System.out.println("Compute time (nanos): " + cpu); 		System.out.println("Wait time (nanos): " + wait); 		System.out.println("Formula: " + numberOfCPU + " * " 				+ targetUtilization + " * (1 + " + waitTime + " / " 				+ computeTime + ")"); 		System.out.println("* Optimal thread count: " + optimalthreadcount); 	} 	/** 	 * Runs the {@link Runnable} over a period defined in {@link #testtime}. 	 * Based on Heinz Kabbutz' ideas 	 * (http://www.javaspecialists.eu/archive/Issue124.html). 	 *  	 * @param task 	 *            the runnable under investigation 	 */ 	public void start(Runnable task) { 		long start = 0; 		int runs = 0; 		do { 			if (++runs &gt; 5) {
			throw new IllegalStateException("Test not accurate");
		}
		expired = false;
		start = System.currentTimeMillis();
		Timer timer = new Timer();
		timer.schedule(new TimerTask() {
			public void run() {
				expired = true;
			}
		}, testtime);
		while (!expired) {
			task.run();
		}
		start = System.currentTimeMillis() - start;
		timer.cancel();
	} while (Math.abs(start - testtime) &gt; EPSYLON);
	collectGarbage(3);
}

private void collectGarbage(int times) {
	for (int i = 0; i &lt; times; i++) {
		System.gc();
		try {
			Thread.sleep(10);
		} catch (InterruptedException e) {
			Thread.currentThread().interrupt();
			break;
		}
	}
}

/**
 * Calculates the memory usage of a single element in a work queue. Based on
 * Heinz Kabbutz' ideas
 * (http://www.javaspecialists.eu/archive/Issue029.html).
 *
 * @return memory usage of a single {@link Runnable} element in the thread
 *         pools work queue
 */
public long calculateMemoryUsage() {
	BlockingQueue queue = createWorkQueue();
	for (int i = 0; i &lt; SAMPLE_QUEUE_SIZE; i++) {
		queue.add(creatTask());
	}
	long mem0 = Runtime.getRuntime().totalMemory()
			- Runtime.getRuntime().freeMemory();
	long mem1 = Runtime.getRuntime().totalMemory()
			- Runtime.getRuntime().freeMemory();
	queue = null;
	collectGarbage(15);
	mem0 = Runtime.getRuntime().totalMemory()
			- Runtime.getRuntime().freeMemory();
	queue = createWorkQueue();
	for (int i = 0; i &lt; SAMPLE_QUEUE_SIZE; i++) {
		queue.add(creatTask());
	}
	collectGarbage(15);
	mem1 = Runtime.getRuntime().totalMemory()
			- Runtime.getRuntime().freeMemory();
	return (mem1 - mem0) / SAMPLE_QUEUE_SIZE;
}

/**
 * Create your runnable task here.
 *
 * @return an instance of your runnable task under investigation
 */
protected abstract Runnable creatTask();

/**
 * Return an instance of the queue used in the thread pool.
 *
 * @return queue instance
 */
protected abstract BlockingQueue createWorkQueue();

/**
 * Calculate current cpu time. Various frameworks may be used here,
 * depending on the operating system in use. (e.g.
 * http://www.hyperic.com/products/sigar). The more accurate the CPU time
 * measurement, the more accurate the results for thread count boundaries.
 *
 * @return current cpu time of current thread
 */
protected abstract long getCurrentThreadCPUTime();

}

然后自己继承这个抽象类并实现它的三个抽象方法,比如下面是我写的一个示例(任务是请求网络数据),其中我指定期望CPU利用率为1.0(即100%),任务队列总大小不超过100,000字节:

package pool_size_calculate;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.lang.management.ManagementFactory;
import java.math.BigDecimal;
import java.net.HttpURLConnection;
import java.net.URL;
import java.util.concurrent.BlockingQueue;
import java.util.concurrent.LinkedBlockingQueue;

public class SimplePoolSizeCaculatorImpl extends PoolSizeCalculator {

@Override
protected Runnable creatTask() {
	return new AsyncIOTask();
}

@Override
protected BlockingQueue createWorkQueue() {
	return new LinkedBlockingQueue(1000);
}

@Override
protected long getCurrentThreadCPUTime() {
	return ManagementFactory.getThreadMXBean().getCurrentThreadCpuTime();
}

public static void main(String[] args) {
	PoolSizeCalculator poolSizeCalculator = new SimplePoolSizeCaculatorImpl();
	poolSizeCalculator.calculateBoundaries(new BigDecimal(1.0), new BigDecimal(100000));
}

}

/**

  • 自定义的异步IO任务
  • @author Will

*/
class AsyncIOTask implements Runnable {

@Override
public void run() {
	HttpURLConnection connection = null;
	BufferedReader reader = null;
	try {
		String getURL = "http://baidu.com";
		URL getUrl = new URL(getURL);

		connection = (HttpURLConnection) getUrl.openConnection();
		connection.connect();
		reader = new BufferedReader(new InputStreamReader(
				connection.getInputStream()));

		String line;
		while ((line = reader.readLine()) != null) {
			// empty loop
		}
	}

	catch (IOException e) {

	} finally {
		if(reader != null) {
			try {
				reader.close();
			}
			catch(Exception e) {

			}
		}
		connection.disconnect();
	}

}

}

得到的输出如下:

Target queue memory usage (bytes): 100000
createTask() produced pool_size_calculate.AsyncIOTask which took 40 bytes in a queue
Formula: 100000 / 40
* Recommended queue capacity (bytes): 2500
Number of CPU: 4
Target utilization: 1
Elapsed time (nanos): 3000000000
Compute time (nanos): 47181000
Wait time (nanos): 2952819000
Formula: 4 * 1 * (1 + 2952819000 / 47181000)
* Optimal thread count: 256

推荐的任务队列大小为2500,线程数为256,有点出乎意料之外。我可以如下构造一个线程池:

ThreadPoolExecutor pool =
 new ThreadPoolExecutor(256, 256, 0L, TimeUnit.MILLISECONDS, new LinkedBlockingQueue(2500));

原创文章,转载请注明: 转载自并发编程网 – ifeve.com本文链接地址: 如何合理地估算线程池大小?


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posted @ 2019-09-18 12:54  星朝  阅读(412)  评论(0编辑  收藏  举报