LeetCode--Best Time to Buy and Sell Stock II

题目:

Say you have an array for which the ith element is the price of a given stock on day i.

Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). However, you may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).

代码:

    int maxProfit(vector<int>& prices) {
        int max = 0;
        for(int i = 1; i < prices.size(); ++i)
        {
            if(prices[i] > prices[i-1])
                max += prices[i] - prices[i-1];
        }
        return max;
    }

找出所有后一天比前一天价钱高的,其总和就是结果.