摘要:
题目传送门:1093. Air Express 题目本身没有什么思维上的难度主要考察思维的严密性,注意有可能weight3 * rate3 2 using namespace std; 3 4 int min(int a,int b,int c); 5 6 int main(){ 7 int weight1,weight2,weight3,rate1,rate2,rate3,rate4,weight,set_number = 1; 8 while(cin >> weight1 >> rate1){ 9 cin >> weight2 >> rate 阅读全文