Daily Coding Problem: Problem #954

复制代码
/**
 * This problem was asked by Google.
A unival tree (which stands for "universal value") is a tree where all nodes under it have the same value.
Given the root to a binary tree, count the number of unival subtrees.
For example, the following tree has 5 unival subtrees:
    0
   / \
  1   0
     / \
    1   0
   / \
  1   1
 * */

class Node(value_: Int) {
    var value = value_
    var left: Node? = null
    var right: Node? = null
}

class Problem_954 {
    /**
     * solution: check whether if unival tree:
     * 1. leaf node
     * 2. children node has save value
     * */

    fun countUnivalTree(root:Node?):Int{
        return helperCount(root)
    }

    private fun helperCount(node:Node?):Int{
        if (node == null){
            return 0
        }
        if (node.left==null && node.right==null){
            return 1
        }
        var count = 0
        if (node.left?.value == node.right?.value){
            count++
        }
        if (node.left!=null){
            count += helperCount(node.left!!)
        }
        if (node.right!=null){
            count += helperCount(node.right!!)
        }
        return count
    }
}
复制代码

 

posted @   johnny_zhao  阅读(21)  评论(0编辑  收藏  举报
编辑推荐:
· AI与.NET技术实操系列(二):开始使用ML.NET
· 记一次.NET内存居高不下排查解决与启示
· 探究高空视频全景AR技术的实现原理
· 理解Rust引用及其生命周期标识(上)
· 浏览器原生「磁吸」效果!Anchor Positioning 锚点定位神器解析
阅读排行:
· DeepSeek 开源周回顾「GitHub 热点速览」
· 物流快递公司核心技术能力-地址解析分单基础技术分享
· .NET 10首个预览版发布:重大改进与新特性概览!
· AI与.NET技术实操系列(二):开始使用ML.NET
· .NET10 - 预览版1新功能体验(一)
历史上的今天:
2020-08-02 1249. Minimum Remove to Make Valid Parentheses (Solution 2: Two ArrayList)
2020-08-02 1249. Minimum Remove to Make Valid Parentheses (Solution 1: BFS)
2020-08-02 125. Valid Palindrome
点击右上角即可分享
微信分享提示