149. Max Points on a Line
package LeetCode_149 /** * 149. Max Points on a Line * https://leetcode.com/problems/max-points-on-a-line/ * * Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. Example 1: Input: [[1,1],[2,2],[3,3]] Output: 3 Explanation: ^ | | o | o | o +-------------> 0 1 2 3 4 * */ class Solution { /* * solution: math, get slope of two point: (y2-y1)/(x2-x1) * Time complexity:O(n^2), Space complexity:O(n) * */ fun maxPoints(points: Array<IntArray>): Int { var res = 0 if (points == null || points.isEmpty()) { return 0 } if (points.size <= 2) { return points.size } val n = points.size //val map = HashMap<String, Int>() val map = HashMap<Double, Int>() for (i in 0 until n) { map.clear() //key is slope of a point //value is the count of same slope var duplicate = 0 var sameX = 0 for (j in (i+1) until n) { if (i == j) { continue } val deltaX = points[j][0] - points[i][0] val deltaY = points[j][1] - points[i][1] //the point overlapping if (deltaX == 0 && deltaY == 0) { duplicate++ //avoid case:[[1,1],[1,1],[1,1]] //continue } if (points[j][0] == points[i][0]) { sameX++ continue } val slope = (points[j][1] - points[i][1]).toDouble() / (points[j][0] - points[i][0]).toDouble() if (map.contains(slope)) { map.put(slope, map.get(slope)!! + 1) } else { map.put(slope, 2) } res = Math.max(res, map.get(slope)!! + duplicate) } res = Math.max(res, sameX) } return res } //return the greatest common divisor /*private fun gcd(a: Int, b: Int): Int { if (b == 0) { return a } return gcd(b, a % b) }*/ }